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Ratling [72]
3 years ago
9

Ivan is putting books in his bookcase. He has

Mathematics
2 answers:
tino4ka555 [31]3 years ago
4 0

151 books

There are 225 books, and 74 have already been placed on the shelf. Subtract 225 minus 74 to find that Ivan needs to place 151 more books on the shelf.

Licemer1 [7]3 years ago
3 0

Answer:

151

Step-by-step explanation:

because 225-74 =151

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Phoenix [80]

Answer:

3

Step-by-step explanation:

4 0
3 years ago
2 1⁄4 × 1 1⁄2 × 5⁄3 =
omeli [17]

Answer:

45/8 = 5,625

Step-by-step explanation:

2\frac{1}{4} × 1\frac{1}{2} × \frac{5}{3} = 9/4 × 3/2 × 5/3 = 9/4 × 1/2 × 5 = 45/8 = 5,625

8 0
3 years ago
Can someone help me ?
vfiekz [6]

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The last answer choice is correct, I am pretty sure.

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8 0
3 years ago
Read 2 more answers
2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

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75t + 112.5 = 90t

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t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

Read more:

brainly.com/question/24234606

6 0
1 year ago
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What set of numbers can represent the side lengths,in centimeters, of a right triangle
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