Answer:
<em>LCM</em> = 
Step-by-step explanation:
Making factors of 
Taking
common:

Using <em>factorization</em> method:

Now, Making factors of 
Taking
common:

Using <em>factorization</em> method:

The underlined parts show the Highest Common Factor(HCF).
i.e. <em>HCF</em> is
.
We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

Using equations <em>(1)</em> and <em>(2)</em>:

Hence, <em>LCM</em> = 
-8k+8m+5
I think this is the answer
Answer:
The slope is -3/7 so B
Step-by-step explanation:
Just turn this into slope-intercept form.
what you do is subtract 3x so that it's moved to the right side.
It should look like this -7y = 12 - 3x
Then just divide all numbers by 7 so everything is simplified
It should look like this y = -3/7x - 12/7
pls mark brainliest because i didn't waste you time lol
Step-by-step explanation:
<h2>a - b = a + (-b)</h2><h2>a + b = a - (-b)</h2>
for any real numbers