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velikii [3]
3 years ago
9

An engineer makes a model of a bridge using a scale of 1 inch = 3 yards. The length of the actual bridge is 50 yards. What is th

e length of the model?
Mathematics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

16\frac{2}{3}\approx 16.67 inches.

Step-by-step explanation:

We have been given that an engineer makes a model of a bridge using a scale of 1 inch = 3 yards. The length of the actual bridge is 50 yards.

To find the length of the model, we will use proportions as:

\frac{\text{Length of model}}{\text{Actual length}}=\frac{1\text{ inch}}{\text{3 yards}}

\frac{\text{Length of model}}{50\text{ yards}}=\frac{1\text{ inch}}{\text{3 yards}}

\frac{\text{Length of model}}{50\text{ yards}}*50\text{ yards}=\frac{1\text{ inch}}{\text{3 yards}}*50\text{ yards}

\text{Length of model}=\frac{50}{3}\text{ inch}

\text{Length of model}=16\frac{2}{3}\text{ inch}

Therefore, the length of model is 16\frac{2}{3}\approx 16.67 inches.

AlladinOne [14]3 years ago
7 0
<span>16.6666666667 
 
To solve the problem, do 50 divided by 3. This will give you how many inches the model is.


</span>
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nika2105 [10]
Let's call the distance from the beach to the playground x.
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There are three right triangles we can work with.

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Triangle with sides 27, x and y. Here y is the hypotenuse so we get 27^{2} + x^{2} = y^{2}

Triangle with sides z, y and (48+27). Here (48+27) is the hypotenuse so we get y^{2} + z^{2} = (27+48)^{2}. That is, y^{2} + z^{2} = 5625

We have 3 equations and 3 unknowns (x, y and z). So let's take the last equation: y^{2} + z^{2} = 5625 and replace z^{2} and y^{2} using expressions that contain an expression in terms of x from the first two equations we came up with.

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∴ The price after tax  = 100% + 4% = 104%

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The answer is:  " x = 105.41 " . 

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Explanation:

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Divide each side of the equation by "3" ;

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         →   " x = 105.41 " .

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 Hope this helps!

    Best wishes to you!

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