Answer: 2.1×10^4
Step-by-step explanation:
7×3×10^3
First you multiply 7×3 = 21
Then add the rest 21×10^3
Then simplify 2.1×10^4
You can check this since:
7×3000 = 21000
When simplified
2.1×10^4
Q=M-2P/3
because in order to solve for a variable you have to get alone. Make sense?
Answer:
![\boxed{ \bold{ \huge{ \boxed{ \sf{72}}}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Cbold%7B%20%5Chuge%7B%20%5Cboxed%7B%20%5Csf%7B72%7D%7D%7D%7D%7D)
Step-by-step explanation:
Given data : 68 , 69 , 71 , 71 , 71 , 73 , 74 , 75 , 75 , 78
N ( total number of observation ) = 10
<u>Finding</u><u> </u><u>the</u><u> </u><u>position</u><u> </u><u>of</u><u> </u><u>median</u>
![\boxed{ \sf{median = { (\frac{n + 1}{2} )}^{th \: item} }}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%7Bmedian%20%3D%20%20%20%7B%20%28%5Cfrac%7Bn%20%2B%201%7D%7B2%7D%20%29%7D%5E%7Bth%20%5C%3A%20item%7D%20%7D%7D)
![\dashrightarrow{ \sf{median = { (\frac{10 + 1}{2} )}^{th \: item}}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7Bmedian%20%3D%20%20%7B%20%28%5Cfrac%7B10%20%2B%201%7D%7B2%7D%20%29%7D%5E%7Bth%20%5C%3A%20item%7D%7D%7D%20)
![\dashrightarrow{ \sf{median = {( \frac{11}{2}) }^{th \: item}} }](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%20%5Csf%7Bmedian%20%3D%20%20%7B%28%20%5Cfrac%7B11%7D%7B2%7D%29%20%7D%5E%7Bth%20%5C%3A%20item%7D%7D%20%7D)
![\dashrightarrow{ \sf{ median = {5.5}^{th \: item}}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%20median%20%3D%20%20%20%7B5.5%7D%5E%7Bth%20%5C%3A%20item%7D%7D%7D%20)
item is the average of 5 th and 6 th items.
Now, <u>Finding</u><u> </u><u>the</u><u> </u><u>median</u>
![\dashrightarrow{ \sf{median = \frac{ {5}^{th}item + {6}^{th} item}{2} }}](https://tex.z-dn.net/?f=%20%20%5Cdashrightarrow%7B%20%5Csf%7Bmedian%20%3D%20%20%5Cfrac%7B%20%7B5%7D%5E%7Bth%7Ditem%20%2B%20%20%7B6%7D%5E%7Bth%7D%20%20item%7D%7B2%7D%20%7D%7D)
![\dashrightarrow{ \sf{ \frac{71 + 73}{2} }}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%20%5Cfrac%7B71%20%2B%2073%7D%7B2%7D%20%7D%7D)
![\dashrightarrow{ \sf{ \frac{144}{2} }}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B%20%5Cfrac%7B144%7D%7B2%7D%20%7D%7D)
![\dashrightarrow{ \sf{72}}](https://tex.z-dn.net/?f=%20%5Cdashrightarrow%7B%20%5Csf%7B72%7D%7D)
Hope I helped!
Best regards! :D
The value of the digit in the tenths place is 7. The value of the digit in the hundredths place is 7. The first number to the right of the decimal is in the tenths place and the second number to the right is in the hundredths place. The 0 is in the ones place and is the first number to the left of the decimal.
Hope this helps!
The long way to compute the sum is to expand each number completely, then add:
3.61 * 10^5 = 3.61 * 100,000 = 361,000
6.05 * 10^6 = 6.05 * 1,000,000 = 6,050,000
Then
3.61 * 10^5 + 6.05 * 10^6 = 6,411,000 = 6.411 * 10^6
A shorter way would be to expand the larger of the two numbers until the powers of 10 match up, then add:
6.05 * 10^6 = 60.5 * 10^5
Then
3.61 * 10^5 + 60.5 * 10^5 = (3.61 + 60.5) * 10^5 = 64.11 * 10^5 = 6.411 * 10^6