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3 years ago

When constructing a line parallel to a given line, you will be

Mathematics

2 answers:

Olenka [21]3 years ago

6 0

I would agree with A. Copying a segment.

Hope this helps you.

siniylev [52]3 years ago

5 0

I believe it would be A. copying a segment, because with a parallel line the lines will not be intersecting, and copying the segment would be the only answer to give you lines that don't intersect.

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F(n)=n-2<br> g(n)=4n-1<br> f{g(n)}=?

Dennis_Churaev [7]

9514 1404 393

Answer:

f(g(n)) = 4n-3

Step-by-step explanation:

f(g(n)) = f(4n -1) = (4n -1) -2

f(g(n)) = 4n -3

3 0

3 years ago

The formula for simple interest is I = Prt. What is the principal (P) if you earn $300 in interest (I) at a rate of 5% (r) for 6

mel-nik [20]

What is this, never seen anything like it before:(

6 0

3 years ago

Suppose the mean height of women age 20 years or older in a certain country is 62.7 inches. One hundred randomly selected women

zmey [24]

Answer: No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

Step-by-step explanation:

Since we have given that

$H_0:\mu =62.7\\\\H_a:\mu \neq 62.7$

Mean height = 61.5 inches

Standard deviation = 4.4 inches

n = 100

So, test statistic value would be

$z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{61.5-62.7}{\dfrac{4.4}{\sqrt{100}}}\\\\z=\dfrac{-1.2}{0.44}\\\\z=-2.727$

At 10% level of significance, in two tail test ,

z = 1.28

Since 1.28 > -2.727

So, we will accept the null hypothesis.

Hence, No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

7 0

4 years ago

—16t^2 + 64t + 3<br> Please help as soon as possible 33 points if you do it!!

aev [14]

Answer:

51t^3

Step-by-step explanation:

64+3=67

67 +(-16)=51

t^2 +t= t^3

now you just add them up but they cant be combined because one is a number and the other a variable w an exponent so we just get 51t^3

6 0

3 years ago

Read 2 more answers

Below, the two-way table is given for a class of students. Juniors Seniors Free Freshmen Sophomore Male 4 6 2 2. Female 3 4 6 3

77julia77 [94]

Answer:

$Pr = 7\%$

Step-by-step explanation:

Given

See attachment for graph

Required

Find P(Junior|Male)

To do this, we first calculate the total students.

$Total = 4 + 6 + 2 + 2 + 3 + 4 + 6 + 3$

$Total = 30$

Next, select the value in the cell that intersects Male and Junior

$Male\ and\ Junior = 2$

Hence, the probability is

$Pr = \frac{Male\ and\ Junior}{Total}$

$Pr = \frac{2}{30}$

$Pr = 0.067$

Express as percentage

$Pr = 0.067*100\%$

$Pr = 6.7\%$

Approximate

$Pr = 7\%$

5 0

3 years ago

Read 2 more answers