A)
B)
Oblicz obwod i pole trójkata prostokatnego o wysokości h=2√5
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Answer:
Step-by-step explanation:
It is given that a fair six-sided die is rolled twice.
X₁= result of the first roll
X₂=result of the second roll
Let A be the event that X₁>X₂.
A={(2,1),(3,1),(4,1),(5,1),(6,1),(3,2),(4,2),(5,2),(6,2),(4,3),(5,3),(6,3),(5,4),(6,4),(6,5)} = 15
It a fair six-sided die is rolled twice then the total number of outcomes is 36.
We need to find the probability of A.
Therefore, the probability of A is .