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geniusboy [140]
4 years ago
6

Explain the difference between 5 1/4 and 5 -(1/4)

Mathematics
1 answer:
Vanyuwa [196]4 years ago
4 0
One is a positive number and the other one has a negative sign
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just olya [345]

Answer:

Sure

Step-by-step explanation:

7 0
3 years ago
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Solve for x. x/7=-3 <br> -21<br> -10<br> 4<br> 21
frez [133]

Answer:

D  21

Step-by-step explanation: x/7 = 3

isolate x by multiplyig both sides by 7:   (7)(x/7) = (3)(7)

x = 21

5 0
3 years ago
So how can I use compatible numbers to estimate the total cost of the field trip.
Brums [2.3K]
By being able to pair the same things it wills simplify the question adding brackets will hwlp
3 0
4 years ago
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(42) A school only provides bus service
Nostrana [21]

Answer:

~1.8 mile

Step-by-step explanation:

Michael lives at the closest  point to the school (the origin) on Maple Street,  which can be represented by the line  y = 2x – 4.

This means Michael's house will be the intersection point of line y1 (y = 2x - 4) and line y2 that is perpendicular to y1 and passes the origin.

Denote equation of y2 is y = ax + b,

with a is equal to negative reciprocal of 2 => a = -1/2

y2 pass the origin (0, 0) => b = 0

=> Equation of y2:

y = (-1/2)x

To find location of Michael's house, we get y1 = y2 or:

     2x - 4 = (-1/2)x

<=> 4x - 8 = -x

<=> 5x = 8

<=> x = 8/5

=> y = (-1/2)x = (-1/2)(8/5) = -4/5

=> Location of Michael' house: (x, y) = (8/5, -4/5)

Distance from Michael's house to school is:

D = sqrt(x^2 + y^2) = sqrt[(8/5)^2 + (-4/5)^2) =  ~1.8 (mile)

4 0
3 years ago
Dale travels from city A to city B to city C and back to city A. Each city is exactly 120 miles from the other two. His average
Ivahew [28]

Answer:

average\ speed = 36\ mi/hr

Step-by-step explanation:

Given:

Each city is exactly 120 miles from the other two.

Average rate from city A to city B = 60 mi/hr

Average rate from city B to city C = 40 mi/hr

Average rate from city c to city A = 24 mi/hr

We need to find the Dale's average rate for the entire trip.

Solution:

First we find the total time and total distance by following way.

Time taken to travel from A to B = \frac{Distance}{Speed} = \frac{120}{60}= 2\ hr

Time taken to travel from B to C = \frac{Distance}{Speed} = \frac{120}{40}= 3\ hr

Time taken to travel from C to A = \frac{Distance}{Speed} = \frac{120}{24}= 5\ hr

So, total time taken = 2+3+5=10\ hr

Total distance =  120 + 120 + 120 = 360 miles

Using average speed formula.

average\ speed = \frac{Total\ distance}{Total\ time\ taken}

average\ speed = \frac{360}{10}

average\ speed = 36\ mi/hr

Therefore, the average rate for the entire trip average\ speed = 36\ mi/hr

8 0
3 years ago
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