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3 years ago

$4.80 for 6 cans unit rate

1 answer:

5 0

8 cents per can. Or, 8c:1 can
You divide 4.80 and 6 to get the price per can.
Give 5 stars and brainliest answer if this helped please!

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Which ordered pairs in the form (x, y) are solutions to the equation 7x−5y=28?

belka [17]

Answer:7x + -5y = -28

(-4, _)

(1, _)

(_, 14)

Step-by-step explanation:

6 0

2 years ago

Please help me - thankyou :)

olga_2 [115]

It is 6 because 1000 would not be the appropiate answer

3 0

2 years ago

Find the value of n in 7 times 38 plus 3 times 45 minus 56

Alex787 [66]

7 * 38 + 3*45 - 56
use order of operations
(7*38) + (3*45) - 56

266 + 135 - 56

=345

3 0

3 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

Choose the first alternative

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

Probabilities

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

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2 years ago

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xxMikexx [17]

Graph A because a graph of non proportional relationship will not pass through the origin (0,0) hope this helps! Remember to give me a like if it did please and thank you!

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3 years ago