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2 years ago

James has decided to start saving for a cruise over the summer. His money is

Mathematics

1 answer:

romanna [79]2 years ago

7 0

Answer:

f(x)=8x +118

Step-by-step explanation:

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PLEASE HELP. i need to show my work for<br> the correct answer. please help

e-lub [12.9K]

Answer:

I THINK IM WRONG BUT

Step-by-step explanation:

X3 NUZZELS POINCES ON U

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3 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

2 years ago

-3(7+5)<br> What is the value of<br> 22<br> 9(2)?

hodyreva [135]

Answer:

I used the picture to answer the question and the answer was -4

5 0

2 years ago

(e+3)(e-5) expanded and simplified

Zarrin [17]

Step-by-step explanation:

$(e + 3)(e - 5) \\ e \times e + e \times ( - 5) + e \times e + e \times 3 \\ { e}^{2} + ( - 5e) + {e}^{2} + 3e \\ {2e}^{2} + ( - 2e)$

In this type of math equation, you have to multiply all members from the first part with the second part.

Expanded:

$e \times e+e \times (-5)+e \times e+e \times 3$

simplified:

${2e}^{2} + ( - 2e)$

8 0

2 years ago

Given xy+yx+ x-3 (x+y)

Elena-2011 [213]

Xy + yx+ x - 3x - 3y
xy + yx + -2x + 3y

5 0

3 years ago