Answer:
O.186 or 18.6%
Step-by-step explanation:
Let s = event of schizophrenia
B = brain atrophy
From our question we have:
P(s) = probability of those suffering from schizophrenia = 1.5% = 0.015
P(B|S) = probability of brain atrophy = 30% = 0.30
P(S') = 1 - 0.015 = 0.985
P(B|S') = 2% = 0.02
Probability Hinckley suffered from schizophrenia
= P(S|B) = P(B|S)P(S)/P(B|S)P(S)+P(B|S')P(S')
= (0.30x0.015)/(0.30)*(0.015)+(0.02)(0.985)
= 0.0045/0.0045+0.0197
= 0.0045/0.0242
= 0.185950
This is approximately 0.186 or 18.6%
Answer:
The answer is A
Step-by-step explanation:
