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kvasek [131]
3 years ago
6

I really really need help with proving this using a two column proof:

Mathematics
1 answer:
Naddik [55]3 years ago
4 0
I'm sorry i'd like to help, but i'm rlly bad at it too. I just finished that module and i still don't get it....

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3 years ago
Find the area of each parallelogram plz help
xxTIMURxx [149]
Answer:  The area of the parallelogram is:
_______________________________________________________
\frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
 A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
         b = 50.5 in.

         h = 23.25 in.
____________________________________________________________
Method 1)  A = b * h =
                 
                     =  (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as:  1174 <span>⅛ .
</span>____________________________________________________________
Method 2)  A = b * h =
             
                      =  (50 ½ in) * (23 <span>¼ in) =
   
                      =    (</span>\frac{101}{2} in) * (\frac{93}{4}<span> in) ;
</span>___________________________________________________________
Note:  "50 ½ " = [(50*2) + 1 ] / 2  = \frac{101}{2} ;

Note:  "23 ¼ " = [(23*4) + 1 ] / 4  = \frac{93}{4} ;
____________________________________________________________
→  A =  (\frac{101}{2} in) * (\frac{93}{4} in) ;
 
→  A = \frac{(101*93)}{(2*4)}  in² = \frac{9393}{8}  in² ; 
          
→  A = (9393/8) in² =  
         
→  A  = \frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
________________________________________________________
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The problem solution  is given in the attachments.

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