Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions
We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M
The final concentration is 1.5 M
Answer:- d. London dispersion
Explanations:- Carbon dioxide structure is given below:
O=C=O
It has two polar C=O bonds but even then it is non polar molecule as it's linear and the dipole moment of one C=O bond is canceled by it's opposite C=O bond.
being non polar, the only attraction forces present in it are London dispersion forces.
Answer:
l and t
Explanation:
because they are in group one
Answer:
Consequently, what happens when gas obtained by heating slaked lime and ammonium chloride is passed through copper sulphate solution? The HCl in the gas mixture will form hydrochloric and the H+ will react with some of the NH3(aq), forming NH4^+, and with some of the SO4^2-, forming HSO4^-.
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L