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3 years ago

Find the number of hours each person work

Mathematics

1 answer:

Lina20 [59]3 years ago

6 0

J stands for Jon, A stands for Angelica, and C stands for Chaya.

J = C - 3
A = C + 4
C = A - 4

= 196 h

62 + 65 + 69 = 196

Jon worked 62 hours, Chaya worked 65 hours, and Angelica worked 69 hours.

And that's your answer! ^ I hope this helped you! c:

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Express 7. 66 repeating as a ratio of two integers.

OverLord2011 [107]

Method A: 7.6666.... = 7 + 0.6666... = 7 + 2/3 = 21/3 + 2/3 = 23/3

Method B: 10(7.666...) - 1(7.666...) = 76.666... - 7.666... = 69.000...
(10 - 1)(7.666...) = 69
7.666... = 69/9 = 23/3

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3 years ago

What is the answer to the whole thing? I'm having trouble with my homework.

notsponge [240]

Y=8,4,2,-2 linear and in that order

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3 years ago

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Yoo wsg whats he units please tell meeee

dimaraw [331]

Answer:

wsp, answer is 5,5 i'm pretty sure

Step-by-step explanation:

or its 0.5

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2 years ago

A Table showing Freezing Temperatures in degrees with 2 columns and 6 rows. The First row, F, has the entries, negative 13, nega

Yuki888 [10]

Answer:

5F + -9 C= 160 39°F = 3.9

Step-by-step explanation:

A Table showing Freezing Temperatures in degrees with 2 columns and 6 rows. The First row, F, has the entries, negative 13, negative 4, 5, 14, 23. The second column, C, has the entries, negative 25, negative 20, negative 15, negative 10, negative 5.

The table shows temperatures below freezing measured in different units. Complete the equation in standard form to represent the relationship between F, a temperature measured in degrees Fahrenheit, and C, a temperature measured in degrees Celsius.

5F + -9 C = 160

39°F = 3.9°C rounded to the nearest tenth of a degree

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3 years ago

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In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. If there were 45 basket

-BARSIC- [3]

Answer:

B. r + l = 45; 2r + 3l = 96

39 regular; 6 long-distance

Step-by-step explanation:

There were 45 baskets, so

(1) r + l = 45

There were 96 points in the game, so

(2) 2r + 3l = 96

Solve equation (1) for l

l = 45 – r Substitute the value for l in Equation (2)

2r + 3(45 – r) = 96 Remove parentheses

2r + 135 - 3r = 96 Combine like terms

-r + 135 = 96 Subtract 135 from each side

-r = -39 Multiply each side by -1

r = 39 Substitute the value of r in Equation (1)

39 + l = 45 Subtract 39 from each side

l = 6

===============

Check:

(1) 39 + 6 = 45

45 = 45

(2) 2×39 + 3×6 = 96

78 + 18 = 96

96 = 96

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3 years ago