The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.
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<h3>How to represent equation in slope intercept form?</h3>
The equation in slope intercept form is represented as follows;
y = mx + b
where
Therefore,
perpendicular lines follows the rule as follows;
m₁m₂ = -1
Therefore,
y - 4 = -(x - 6)
y - 4 = -x + 6
y = -x + 6 + 4
y = -x + 10
Therefore,
-1m₂ = -1
m₂ = 1
Hence, the line passes through (-2, -2).
Therefore,
-2 = 1(-2) + b
b = -2 + 2
b = 0
Therefore, the equation is as follows;
y = x
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Answer:
l=15
Step-by-step explanation:
let length=l
width=w
l=3w-2
w=(l+2)/3
Perimeter P=2(l+w)=2[l+(l+2)/3]=2(4l+2)/3≤43
2(4l+2)≤129
8l+4≤129
8l≤125
l≤125/8
so l=15
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P=2(l+w)=2(3w-2+w)=8w-4≤43
8w≤47
w≤47/8
l≤141/8-2
l≤125/8
l=15
Answer:
8 4/20
0.2
-8 1/10
Step-by-step explanation:
Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
1a) Some of the interior angles of a 15-gon must be 13 x 180=2340 degrees. Since it’s regular, the total is shared equally among the interior angles. 2340/15=156 degrees
