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san4es73 [151]
3 years ago
10

Please help me thanks

Mathematics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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How do you solve a+(a+1)+(a+2)=48 step by step???
Tcecarenko [31]
Start with parenthesis first.
so a+a+2a+48
Then add all like terms.
4a=48
Then solve for a by dividing 4 from 48.
a=12
8 0
3 years ago
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
3 years ago
Find the missing side of this right<br> triangle.<br> 19<br> X<br> X =<br> 16<br> ✓[?]
julia-pushkina [17]

Answer:

x = sqrt(105)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

16^2 + x^2 = 19^2

256 + x^2 = 361

x^2 = 361 -256

x^2 =105

Take the square root of each side

sqrt(x^2) = sqrt(105)

x = sqrt(105)

8 0
2 years ago
The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324π cubic centimeters. The area of the
stealth61 [152]
Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase

 

given
h=9
v=324pi
324pi=9(basearea)
divide both sides by 9
36pi=areabase

the area of te base is 36pi square cm (put 36 in the blank since th pi is alredy there)
3 0
3 years ago
Read 2 more answers
Please help me please please please
algol13

Answer:

20

Step-by-step explanation:

The lower quartile Q₁ is the value at the left side of the box, that is

Q₁ = 20

5 0
3 years ago
Read 2 more answers
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