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2 years ago

Consider that point A is reflected across the y-axis. What is the distance between point A and the point of its reflection?

Mathematics

1 answer:

Arisa [49]2 years ago

7 0

Answer:

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ), thus

A(3, 4 ) → A'(- 3, 4 )

Since the point A and it's reflection lie on a horizontal line then

distance between = | 3 + 3 | = | 6 | = 6

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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

borishaifa [10]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information.

B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

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2 years ago

The Brown family needs to rent a truck for their upcoming move. Express Movers will charge them $25 for the first day and $0.80

svet-max [94.6K]

Answer:

Hope this Helps Dork! :)

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2 years ago

Read 2 more answers

Make x the subject in the relation

tatyana61 [14]

Cant read your writing-

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2 years ago

I need help this dosent make sense

horsena [70]

1. 7 + -10 = -3.
2. -3 + -8 = -11
3. 4 + -5 = -1
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(You basically need to add negative numbers to positive numbers in order to get negative numbers.)

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3 years ago

1. If the length of a rectangle is 6 more than its width, and its perimeter is 48

Salsk061 [2.6K]

For this case we have that by definition, the perimeter of the rectangle is given by:

$P = 2w + 2L$

Where:

W: Is the width of the rectangle

L: is the length of the rectangle

According to the data we have:

$L = 6 + w\\P = 48$

Substituting:

$48 = 2w + 2 (6 + w)\\48 = 2w + 12 + 2w\\48 = 4w + 12\\48-12 = 4w\\36 = 4w\\w = \frac {36} {4}\\w = 9$

So, the width of the rectangle is 9 inches

$L = 6 + 9 = 15$

So, the length of the rectangle is 15 inches

Answer:

the width of the rectangle is 9 inches

the length of the rectangle is 15 inches

5 0

2 years ago