Answer:
The value of c for he given figure is 7.4
Step-by-step explanation:
Given figure of circle with two chords meeting outside the circle
Let The points A, D , E , C are on the circle
And The chords AB and CD meets at points B
The measure of AD = 20
The measure of BD = 10
So. The measure of AB = 20 + 10 = 30
The measure of CE = c
The measure of EB = 14
So, The measure of CB = c + 14
Now, <u>From the property of circle </u>
AB × BD = CB × EB
Or, ( AD +BD ) × BD = ( CE + EB ) × EB
Or, ( 20 + 10 ) × 10 = ( c + 14 ) × 14
or, 30 × 10 = c × 14 + 196
Or, 300 - 196 = c × 14
Or c × 14 = 104
∴ c =
I.e c = 7.4
Hence The value of c for he given figure is 7.4 Answer