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sergejj [24]
3 years ago
13

What is this as answer to this problem 3(2x+2)=96

Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer:

×=16

Step-by-step explanation:

distribute 3 into the () so it would be 6x+6=96. subtract 6 to 96= 90. 90 divide by 2=16

Whitepunk [10]3 years ago
5 0
The answer to this is 15
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In the word flashlight what is the ratio of vowels to total letters
Lena [83]

Answer:

2 to 10 or 1 to 5

Step-by-step explanation:


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Solve the equation by completing the square. Round the square. Round to the nearest hundredth if necessary. x2 - 3x -12 =0
dmitriy555 [2]
A:5.27,-2.27 should be your answer
5 0
3 years ago
Edward can run 1/2 mile in 300 seconds what is edwards unit rate
Vilka [71]
Rate/ speed = distance / time;
= 1/2mile / 300 seconds;
= 0.001666666..... mile/second
7 0
4 years ago
Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.8. (Round your ans
Alenkinab [10]

Answer:

a) 0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

b) 0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 50, \sigma = 1.8

(a) If the distribution is normal, what is the probability that the sample mean hardness for a random sample of 17 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{17}} = 0.4366

This probability is 1 subtracted by the pvalue of Z when X = 51. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.4366}

Z = 2.29

Z = 2.29 has a pvalue of 0.9890

1 - 0.989 = 0.011

0.011 = 1.1% probability that the sample mean hardness for a random sample of 17 pins is at least 51

(b) What is the (approximate) probability that the sample mean hardness for a random sample of 45 pins is at least 51?

Here n = 17, s = \frac{1.8}{\sqrt{45}} = 0.2683

Z = \frac{X - \mu}{s}

Z = \frac{51 - 50}{0.0.2683}

Z = 3.73

Z = 3.73 has a pvalue of 0.9999

1 - 0.9999 = 0.0001

0.0001 = 0.1% probability that the sample mean hardness for a random sample of 45 pins is at least 51

8 0
3 years ago
What is the distance between nicholas's school and the post office?
aleksklad [387]
Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

d= \sqrt{(-2-3)^2+(-2-2)^2}  \\  \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16}  \\  \\  \sqrt{41} =\bold{6.4} \ units



Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

d= \sqrt{(1-(-3))^2+(-1-2)^2}  \\  \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9}  \\  \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}
4 0
3 years ago
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