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Crazy boy [7]
3 years ago
15

A plastic storage bin is shaped like a rectangular prism. The height of the bin is 9 inches. The bottom of the bin has an area o

f 180 square inches. What is the volume of the storage bin? Enter your answer in the box. in³
Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0

Answer:

<em>1620in³</em>

Step-by-step explanation:

Volume of a rectangular prism = BH

B is the Base area

H is the height of the prism.

Given

B = 180in²

H = 9in

get the volume of the prism

Volume of the prism  = 180 * 9

Volume of the prism  = 1620in³

<em>Hence the volume of the rectangular prism is 1620in³</em>

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4 minus 1.2<br>what is it 2.8 instead of 3.2? ​
MatroZZZ [7]

Answer:

2.8 is correct

Step-by-step explanation:

  4.0

-   1.2

The 0 becomes 10

10 - 2 = 8

The 4 becomes 3

3 - 1 =2

2.8

3 0
3 years ago
Write the ratio as a fraction in lowest terms.<br> 15 minutes to 3 hours
mel-nik [20]

Answer:

Part A is 5/6 of the whole

Part B is 1/6 of the whole

Solution:

Assuming there are no other parts,

the Whole = A + B is the denominator:

Whole = 15 + 3 = 18

Part A = 15 and Part B = 3 are numerators for each fraction.

The fractions are then:

15/18 and 3/18

Meaning:

Part A is 15/18 of the whole

Part B is 3/18 of the whole

Reducing the fractions, it is also true that:

Part A = 5/6 of the whole

Part B = 1/6 of the whole

7 0
3 years ago
Read 2 more answers
Which values from the set (-6,-4,-2,0,2,4,6) Satisfy this inequality? 3+1/2x&gt;4
VMariaS [17]

Answer:-6 and -4

Step-by-step explanation:

5 0
3 years ago
if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile
Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

4 0
1 year ago
A circle is inscribed inside a square as shown. If graphed on the coordinate plane, the coordinates of the center of the circle
avanturin [10]
Length of side of the square = 2r 
where r=radius of inscribed circle

Given an inscribed circle
Centre of circle , O(2,5)
Point on circle, P(-2,2)
Radius of circle
=distance OP
=sqrt((2-(-2))^2+(5-2)^2)
=sqrt(4^2+3^2)
=5

Therefore area of square
=(2r)^2
=(2*5)^2
=10^2
=100
8 0
4 years ago
Read 2 more answers
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