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IgorC [24]
3 years ago
6

Whats the answer for 1/2 + 1/8 + 3/4

Mathematics
1 answer:
HACTEHA [7]3 years ago
8 0
You have to find a common denominator, in this question it would be 8. Then take the 1/2 and multiply the numerator and denominator by 4 so you get 4/8. You would leave the 1/8 alone. After take the 3/4 and multiply the numerator and denominator by 2 so you’ll get 6/8. Now you can add 4/8+1/8+6/8 which equals 11/8 or 3 1/8
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20% of $5.05 = $____<br> Please hellp
RideAnS [48]

Answer:

1.01

Step-by-step explanation:

4 0
4 years ago
Y = 3/5x + 1, 5y = 3x - 2, 10x - 6y = -4<br> is it perpendicular, parallel, neither
Ber [7]

Answer:

y=\frac{3}{5} x+1 and 5y=3x-2 are parallel.

10x-6y=-4 is neither parallel nor perpendicular.

Step-by-step explanation:

First, you have to simplify each equation in terms of y.

y=\frac{3}{5} x+1\\5y=3x-2\\10x-6y=-4

Your first equation is already in terms of x, so simplify your second equation.

5y=3x-2\\y=\frac{3}{5} x-\frac{2}{5}

Now you can simplify your third equation.

10x-6y=-4\\-6y=-10x-4\\y=\frac{5}{3} x+\frac{2}{3}

These are your three equations in terms of y:

y=\frac{3}{5} x+1\\\\y=\frac{3}{5} x-\frac{2}{5} \\\\y=\frac{5}{3} x+\frac{2}{3}

Now, all you have to know is how to tell using your slope if a line is parallel or perpendicular to another.

Two parallel lines will have the exact same slope.

Two perpendicular lines will have slopes which are opposite reciprocals. For example, a line with a slope of 2 is perpendicular to a line with a slope of -\frac{1}{2}, as they have opposite signs and are reciprocal (2/1 versus 1/2) to each other.

Your first two equations have the same slope and are therefore parallel.

Your third equation is a reciprocal, but it is not opposite, and is therefore not parallel nor perpendicular.

5 0
3 years ago
Solve the equation <br> 5x + 8 - 3x = 10
ra1l [238]

Answer: X=1


Step-by-step explanation: 5x+8-3x=10

Combine like terms; 5x + (-3x) = 2x

Rewrite; 2x+8=10

Get “x” alone; 2x+8=10

-8. -8

Simply divsion; 2x=2

X=1


6 0
3 years ago
Using the quadratic formula to solve 11x²-4x=1 What are The values of X?
Anvisha [2.4K]
11x^2 - 4x = 1
11x^{2} - 4x - 1 = 1 - 1
11x^{2} - 4x - 1 = 0
x = \frac{-(-4) \± \sqrt{(-4)^{2} - 4(11)(-1)}}{2(11)}
x = \frac{4 \± \sqrt{16 + 44}}{22}
x = \frac{4 \± \sqrt{60}}{22}
x = \frac{4 \± 2\sqrt{15}}{22}
x = \frac{2 \± \sqrt{15}}{11}
x = \frac{2 + \sqrt{15}}{11}\ \bold{or}\ x = \frac{2 - \sqrt{15}}{11}
8 0
4 years ago
Read 2 more answers
Are any solutions possible for this problem..
storchak [24]

The answer is all real numbers because -2x-6=-2x-6

7 0
3 years ago
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