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likoan [24]
2 years ago
14

A cone is placed inside a cylinder as shown. The radius of the cone is half the radius of the cylinder. The height of the cone i

s equal to the radius of the cylinder. What is the volume of the cone in terms of the radius, r? What is the ratio of the radius of a circle to its circumference?
Mathematics
2 answers:
kondaur [170]2 years ago
4 0
Given:
Volume of the cone = π r² h/3

radius of the cone is half the radius of the cylinder ⇒ r/2
height of the cone is equal to the radius of the cylinder. ⇒ r

V = 3.14 * (r/2)² * r/3
V = 3.14 * r²/4 * r/3
V = 3.14r³ / 12

Ivanshal [37]2 years ago
3 0

Answer:


C.   V = \frac{1}{12} π r^{3}

Step-by-step explanation:

<em>A. </em><em>  V = \frac{1}{3} π r^{2} h</em>


B.  V = \frac{1}{6} π r^{2}


C.   V = \frac{1}{12} π r^{3}


D.   V = 2 π r^{3}

<em>π Is Meant To be </em><em>π</em>

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fenix001 [56]
Sandi did not follow PEMDAS. She added before multiplying and dividing. Her answer should be 18 because 6 • 4 = 24, 2 / 2 = 1, 24 + 1 = 25, 25 - 7 = 18
3 0
3 years ago
R is the interior of angle TUV. The measure of RUV=30degrees, the measure of TUV=3x+16, and the measure of TUR=x+10. Find x and
choli [55]

Given

R is the interior of ∠ TUV.

m∠ RUV=30degrees, m∠ TUV=3x+16, and m∠ TUR=x+10.

Find the value of x and the m ∠TUV.

To proof

As given in the question

m ∠TUV=3x+16, and m ∠TUR=x+10

thus

m∠ RUV =  m∠ TUV - m∠ TUR

            = 3x + 16 - x -10

            = 2x + 6

As given

m ∠RUV=30°

compare both the values

we get

30 = 2x + 6

24 = 2x

12 = x

put this value in the m ∠TUV= 3x+16

m ∠TUV= 12× 3 +16

            = 52°

Hence proved


7 0
2 years ago
Evaluate (3)^1/6 × (3)^-2/3
Elan Coil [88]
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7 0
1 year ago
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leva [86]

\frac{-18z^{7}y^{5}-9z^{9}y^4+18z^6y^8}{9zy^{2} }= -2z^6y^3-z^8y^2+2z^5y^6


When variables with exponents are divided by each other, you subtract the exponents.

For example:

\frac{x^2}{x^1} = x^{2-1} =x^1

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8 0
3 years ago
M is the midpoint of segment CS. C is at (-8, 2) M is at the origin. What are the coordinates of S?
ahrayia [7]
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)

C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)

a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8

b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2  and y₂ = -2

Then the coordinates of  S are S(8 , -2)
4 0
2 years ago
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