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2 years ago

What type of function has a common rate of change

Mathematics

1 answer:

Veronika [31]2 years ago

3 0

Answer:

linear

Step-by-step explanation:

A linear function has a <em>constant</em> rate of change.

_____

The word "common" is usually used to refer to a shared characteristic of two or more entities. It would not ordinarily be used to describe a characteristic of one function. We're not quite sure what you mean by "has a common rate of change."

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Two dices are thrown. Find the probabilty of getting:

horsena [70]

Answer:

(A) 2/12 or 1/6. (B) 2/12 or 1/6 (C) 4/12 or 1/3.

Step-by-step explanation:

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1 year ago

Can someone help me with these two? Please

avanturin [10]

For 16/18 it would be 8/9
For 10/15 it would be 2/3

4 0

2 years ago

Read 2 more answers

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

3 years ago

With food prices becoming a great issue in the world; wheat yields are even more important. Some of the highest yielding dry lan

Rzqust [24]

Answer:

Option E) 61.6

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100 bushels per acre

Standard Deviation, σ = 30 bushels per acre

We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X>x) = 0.90

We have to find the value of x such that the probability is 0.90

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 100}{30})=0.90$

$= 1 -P( z \leq \displaystyle\frac{x - 100}{30})=0.90$

$=P( z \leq \displaystyle\frac{x - 100}{30})=0.10$

Calculation the value from standard normal table, we have,

$P(z$

$\displaystyle\frac{x - 100}{30} = -1.282\\x = 61.55 \approx 61.6$

Hence, the yield of 61.6 bushels per acre or more would save the seed.

7 0

2 years ago

3^4 + 2 ⋅ 5 = ____. (Input only whole numbers.)

meriva

91

Follow the order of operations.

3^4 + 2 * 5

81 + 2 * 5 (Exponent)

81 + 10 (Multiplication)

91 (Addition)

Please consider marking this answer as Brainliest to help me advance.

5 0

2 years ago