5x - 4. Correct if definetly wrong.
Make a bar graph about the length of letters in an animal's name
For this case, we perform the conversions:
First roll:
![1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x](https://tex.z-dn.net/?f=1%20%5C%20Hectometer%20--------%3E%20100%20%5C%20meters%5C%5C3%20%5C%20Hectometer%20--------%3E%20x)
![x = \frac {3 * 100} {1}\\x = 300 \ meters.](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%20%7B3%20%2A%20100%7D%20%7B1%7D%5C%5Cx%20%3D%20300%20%5C%20meters.)
We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.
1 -----------> 4.2
c -----------> 300
![c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%20%7B300%20%2A%201%7D%20%7B4.2%7D%5C%5Cc%20%3D%2071.42857143%5C%5Cc%20%3D%2071)
You can pack 71 boxes.
Second roll:
![1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.](https://tex.z-dn.net/?f=1%20%5C%20Decametro%20--------%3E%2010%20%5C%20meters%5C%5C7%20%5C%20Decameter%20--------%3E%20x%5C%5Cx%20%3D%20%5Cfrac%20%7B7%20%2A%2010%7D%20%7B1%7D%5C%5Cx%20%3D%2070%20%5C%20meters.)
We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.
1 -----------> 4.2
c -----------> 70
![c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%20%7B70%20%2A%201%7D%20%7B4.2%7D%5C%5Cc%20%3D%2016.66666667%5C%5Cc%20%3D%2016)
You can pack 16 boxes.
Third roll:
1 -----------> 4.2
c -----------> 50
![c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11](https://tex.z-dn.net/?f=c%20%3D%20%5Cfrac%20%7B50%20%2A%201%7D%20%7B4.2%7D%5C%5Cc%20%3D%2011.9047619%5C%5Cc%20%3D%2011)
You can pack 11 boxes.
Thus, in total you can pack![11 + 16 + 71 = 98 \ boxes](https://tex.z-dn.net/?f=11%20%2B%2016%20%2B%2071%20%3D%2098%20%5C%20boxes)
Answer:
98 boxes