Considerando la definición de una ecuación, el número desconocido es 50.
<h3>Definición de ecuación</h3>
Una ecuación es la igualdad existente entre dos expresiones algebraicas conectadas a través del signo de igualdad en la que figuran uno o varios valores desconocidos, llamadas incógnitas, además de ciertos datos conocidos.
Los miembros de una ecuación son cada una de las expresiones que aparecen a ambos lados del signo igual.
<h3>Número desconocido</h3>
En este caso, "La suma de un número con su mitad es igual a 75" puede ser expresado mediante una ecuación, donde consideras que "x" es la incógnita, que representa el número desconocido.
Teniendo en cuenta que la mitad de un número se calcula dividiendo el número por 2, entonces la ecuación queda expresada como:
x + x÷2= 75
O lo que es lo mismo
x + 
x= 75
Resolviendo:
x= 75
x= 75 ÷
x= 75×
<u><em>x=50</em></u>
Finalmente, el número desconocido es 50.
Aprende más sobre ecuaciones con estos ejemplos:
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Answer: The probability would 0.35770234986 or 35%
Step-by-step explanation:
Answer:
- Base = 3 units
- Height = 7 units
- Area = 3 · 7
- = 21 units²
Step-by-step explanation:
Count the squares. The horizontal extent is 3 squares, so is 3 units.
The vertical extent is 7 squares, so is 7 units. We're only concerned with the vertical distance between the horizontal lines at the top and bottom of the figure. The slant distance along the side of the figure is irrelevant.
From there, fill the numbers into the blanks and do the multiplication. "bh" means multiply the Base value by the Height value.
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<em>Comment on units</em>
It is not quite true that 3·7 = 21 units². What is true is that ...
(3 units)·(7 units) = 21 units²
The equal sign should be treated with respect and care. What is found on one side must always be strictly equal to what is found on the other side. You cannot simply add "units²" to one side of the equation because you feel like it. There must be something corresponding on the other side of the equation.
You can actually multiply and divide units (and in Physics, you're expected to do so). The units can be attached to the numbers and treated in the math as though they were a variable. This can be especially helpful in area, volume, time/speed/distance, and unit-rate problems.
Answer:
Step-by-step explanation:
r²+8r=−7
Step 1: Subtract -7 from both sides.
r²+8r−(−7)=−7−(−7)
r²+8r+7=0
Step 2: Use quadratic formula with a=1, b=8, c=7.
r=
Answer:
Step-by-step explanation:
