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3 years ago

Solve for b: a/b = c

Mathematics

2 answers:

Vladimir [108]3 years ago

7 0

May sumagot na btw thank you sa points

irina [24]3 years ago

4 0

Multiply each term by
b

and simplify.
a = cb

Rewrite the equation as
cb = a
Divide each term by
c

and simplify.
b = a/ c

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The length of the rectangle is 4cm less than its width . what are the dimensions of the rectangle if its area is 140

melomori [17]

Let the width of the rectangle be x
Then length =x-4
Area=x(x-4)=140
x²-4x=140
x²-4x-140=0
x²-14x+10x-140=0
x(x-14)+10(x-14)=0
(x-14)(x+10)=0
Therefore,length=14 cm and width=10 cm

8 0

3 years ago

Solve this system by substitution. y = 5x - 15 y = 2x - 6 *Remember to write your answer as a coordinate point (x,y Solve this s

oksano4ka [1.4K]

5x - 15 = 2x - 6
3x = 9
x = 3
Y = 5(3) - 15
Y = 0
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3 years ago

20 Points! Which ordered pair is the best estimate for the solution of the system of equations?

yan [13]

Answer:

The best estimate for the solution is the ordered pair $(-6.5,-3.5)$

Step-by-step explanation:

we have

$y=\frac{3}{2}x+6$ ------> equation A

$y=\frac{1}{4}x-2$ ------> equation B

we know that

using a graphing tool, the solution of the system of equations is the intersection point both graphs

The intersection point is $(-6.4,-3.6)$

therefore

The best estimate for the solution is the ordered pair $(-6.5,-3.5)$

3 0

3 years ago

A rectangle has an area of (12m-30n) square units. Its width is 6 units. Factor the expression for the area to find an expressio

garik1379 [7]

Answer: 2m - 5n

<u>Explanation:</u>

Using long division

6 ) 12m - 30n

width*length = area

6(2m - 5n) = 12m - 30n

5 0

4 years ago

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

4 years ago