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pochemuha
2 years ago
8

Solve for b: a/b = c

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0
May sumagot na btw thank you sa points
irina [24]2 years ago
4 0


Multiply each term by
b

and simplify.
a = cb

Rewrite the equation as
cb = a
Divide each term by
c

and simplify.
b = a/ c
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Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
3 years ago
4x find the degree with steps​
Alex787 [66]

9514 1404 393

Answer:

  1

Step-by-step explanation:

The term has 1 variable, which has no exponent shown. When the exponent is not shown, it is understood to be 1. The degree of the term is the exponent of this single variable, so the degree is 1.

_____

<em>Additional comment</em>

If the term is a product of more than one variable, the degree is the sum of their exponents.

3 0
2 years ago
What is the value of -44
garik1379 [7]
Hi friend!


I presume you mean "What is the absolute value of -44!

Well an absolute value is always positive. So the absolute value of -44 is 44!


Hope I helped!


If not, tell me more clearly what you need!
4 0
3 years ago
Read 2 more answers
Can someone help me real quick
LuckyWell [14K]

Answer:

12 movies

Step-by-step explanation:

If you do not rent any vidoes you will be charged $45 no matter what, so...

Movies + 45 = total charge

each movie is 1.99 and you owe (total charge) $68.88

equation:

1.99x + 45 = 68.88

          -45       -45    (subtract 45 from each side to keep equation balanced)

1.99x = 23.88  (now divide both sides by 1.99 to get x alone)

     x = 12

you rented 12 movies

3 0
2 years ago
2. When there is a strong positive, how do the points look?
motikmotik

When there's a strong positive, the points are: B. Close together.

<h3>Strong Positive Relationship</h3>
  • On a scatter plot, if the data points are close together along the trend line sloping upwards, it means there's a strong positive correlation.
  • Strong positive correlation means the two variables change in the same direction.

Therefore, when there's a strong positive, the points are: B. Close together.

Learn more about strong positive relationship on:

brainly.com/question/15552860

5 0
2 years ago
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