Answer:
58.6.....................
Answer:
W=0.8333*t
2.917 ft³
Step-by-step explanation:
At time t=3, there is 2.5 ft³ of water in the tub
Finding the relation will be;
3=2.5
1=?
Rate=0.8333 ft³/min
W=0.8333 ft³ / min
W=0.8333*t
At t=3.5 will be;
1 min = 0.8333
3.5 min =?
Apply cross-production
3.5*0.8333 =2.917 ft³
Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
I think its B. False if im wrong sorry hope this helped tho :p
