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Slav-nsk [51]
2 years ago
11

Dilate ABC below using A as the center and a scale factor of 2. Leave all construction marks?

Mathematics
1 answer:
irina1246 [14]2 years ago
8 0
<h3>Answer: Check out the diagram below.</h3>

Explanation:

Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.

The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.

Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.

The same set of steps will have us construct point C' as well. AC doubles to AC'

Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.

Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.

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PLEASE HELP (question is in picture)
HACTEHA [7]

Answer:

4*3=12

12*4=

3*3=9

9*2=18

18+48=66

Step-by-step explanation:

8 0
2 years ago
What would my GPA be? Here are my grades.
marta [7]
That is approximately, in order, a C, a C, a B, a D, an A, a B, and an A.

In grade points that is a 2, a 2, a 3, a 1, a 4, a 3, and a 4.

The average of those numbers is about 2.7, so you have a 2.7.

You can raise that by bringing up the D as it is an outlier here.
4 0
3 years ago
10. Both x and y vary inversely with each other. When x is 10, y is 6,which of the following is not a possible pair of correspon
elena55 [62]

9514 1404 393

Answer:

  D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

  y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

  xy = k . . . . . . multiply the above equation by x

  (10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

  y = 60/x

you can multiply them together to see if the product is 60.

  (A) 12×5 = 60

  (B) 15×4 = 60

  (C) 25×2.4 = 60

  (D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

8 0
2 years ago
Which statement is true about the equations –3x + 4y = 12 and 1/4x –1/3 y = 1?The system of the equations has exactly one soluti
iren [92.7K]

Answer:

The system of the equations has no solution; the two lines are parallel.

Step-by-step explanation:

The equations have the same slope. In standard form, this can be seen as the same coefficients for x and y. We will multiply the second equation by -12 to reveal this.

\frac{1}{4} x-\frac{1}{3}y=1 \\-12(\frac{1}{4} x-\frac{1}{3}y=1)\\\frac{-12}{4} x-\frac{-12}{3}y=-12\\-3x+4y=-12

This means the equations are parallel and will never cross. There is no solution.

4 0
2 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

5 0
3 years ago
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