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pychu [463]
4 years ago
10

Solve x^2 + X + 5= 0 using the quadratic formula. what is the solution set?

Mathematics
1 answer:
Pie4 years ago
8 0
\bf ~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{llcccl}
& 1 x^2& +1 x& +5&=0\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
x= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}
\\\\\\
x=\cfrac{-1\pm\sqrt{1^2-4(1)(5)}}{2(1)}\implies x=\cfrac{-1\pm\sqrt{-19}}{2}
\\\\\\
x=\cfrac{-1\pm\sqrt{-1\cdot 19}}{2}\implies x=\cfrac{-1\pm\sqrt{-1}\cdot \sqrt{19}}{2}
\\\\\\
x=\cfrac{-1\pm i \sqrt{19}}{2}
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Answer:

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Step-by-step explanation:

Translation vectors add, and the addition is commutative and associative.

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The first translation adds (-1, 2) to the original coordinates. The second translation adds (2, -1) to the original coordinates. The two translations together add ...

  (-1, 2) +(2, -1) = (-1+2, 2-1) = (1, 1)

to the original coordinates.

The single rule representing this translation is ...

  (x, y) ⇒ (x +1, y +1)

Then the doubly-translated coordinates are ...

  A(-2, -3) ⇒ A"(-1, -2)

  B(5, -1) ⇒ B"(6, 0)

  C(2, 2) ⇒ C"(3, 3)

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If you can buy one can of pineapple chucks for $2 then how many can you buy with $10?
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Step-by-step explanation:

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Distribute

4+4x-8 = 2x+1-x

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Divide

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As per the statement:

Height of the building(h)= 30 feet

Angle of elevation (\theta)= 41°

We have to find the distance of observer from the base of the building.

Using tangent ratio:

\tan \theta= \frac{\text{Opposite side}}{\text{Adjacent side}}

You can see the diagram as shown below.

Opposite side = height of the building = 30 feet.

Adjacent side = distance of observer from the base of the building = x (let)

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