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3 years ago

Can I get help please

Mathematics

2 answers:

Alchen [17]3 years ago

7 0

Answer:

your math questions send me

Morgarella [4.7K]3 years ago

3 0

Answer:

I would say b, but wait for another person to answer and confirm

Step-by-step explanation:

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zaharov [31]

Answer:

(#1 starts at "has two pairs of parallel sides" and checkmark=c, while no checkmark=x)

Step-by-step explanation:

1. c

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8 0

3 years ago

The sides of the base of a right square pyramid are 4 m in length , and its slant height is 8 m. If the lengths of the sides of

hram777 [196]

Answer:

Step-by-step explanation:

We have that the total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base, therefore it would be equal to:

As = 1/2 * p * h + l ^ 2

where l are the sides that measure 4, p is the perimeter that is the sum of the sides, and since there are 4 sides then it would be 16 (4 * 4), h the inclined height is 8, replacing we are left with:

As = 1/2 * 16 * 8 + 4 ^ 2

Ace = 80

Now, they say that the sides and the tilt height are multiplied by 4, the sides now measures 16, therefore the perimeter is 64 (4 * 16), the height would be 32, replacing would be:

As = 1/2 * 64 * 32 + 16 ^ 2

As = 1280

Therefore the factor would be:

1280/80 = 16

This means that to calculate the new surface area, it must be multiplied by the square of the number by which the sides and the inclined height are multiplied, that is, 4 ^ 2 = 16.

5 0

3 years ago

Read 2 more answers

Larger of two numbers is nine less than four times the smaller number if the sum of two numbers is 76 find both numbers

makvit [3.9K]

x + y = 76

x = 4y - 9

4y - 9 + y = 76

5y = 65

y = 13

13 + x = 76

x = 63

8 0

3 years ago

Read 2 more answers

Determine if the equation x^2 + 3y^2= 3 defines y as a function of x

belka [17]

Answer:

y is NOT a function.

Step-by-step explanation:

The equation given to us is:

x² + 3y² = 3

Rearrange the equation:

3y² = 3 - x²

y² = (3 - x²)/3

y² = 1 - (x²)/3

y = ±√(1 - x²/3)

For any equation to be a function, there should be only one output for one input. Which means that for any value of x, there should be only one value of y. However, in this equation, as the underroot gives two values of any terms under it, it shows that if we put any value of x, we'll get 2 values of y. Therefore, y is not a function.

4 0

3 years ago

Margaret is building storage boxes. each box will have a length of 8 feet, a width of 512 feet, and a height of 412 feet. a pint

Lera25 [3.4K]

The surface area of a cuboid is the area of all the six faces of a cuboid. The Paint that is required to paint 3 boxes is 13 pints.

<h3>What is the surface area of a cuboid?</h3>

The surface area of a cuboid is the area of all the six faces of a cuboid. It is given by the formula,

$\rm \text{Surface area of the box}= 2[(Length \times width)+(Width \times Height)+(Length \times height)]$

As it is given the dimensions of the storage box are a length of 8 feet, a width of 5 1/2 feet(5.5 feet), and a height of 4 1/2 feet(4.5 feet). Therefore, the surface area of the box can be written as,

$\rm \text{Surface area of the box}= 2[(Length \times width)+(Width \times Height)+(Length \times height)]$

$\rm \text{Surface area of the box}= 2[(8\times 5.5)+(5.5\times 4.5)+(8 \times 4.5)] = 209.5\ ft^2$

As it is given that the surface area that can be covered with a pint of paint is 50 square feet, therefore, the paint that will be required to paint 209 square feet is,

$\text{Paint Required} = \dfrac{\text{Total area that is needed to be paint}}{\text{Area covered in a pint of paint}}$

$\rm \text{Paint Required} = \dfrac{209.5}{50} = 4.19\ pints$

Now, we know that the surface area of the box is 209 square feet, while the paint required to paint a complete box is 4.19, therefore, the paint that will be required to paint 3 boxes will be,

$\text{Paint required to paint 3 boxes} = 3 \times 4.19 = 12.57 \approx 13$

Hence, the Paint that is required to paint 3 boxes is 13 pints.

Learn more about Surface Area of Cuboid:

brainly.com/question/26403859

4 0

2 years ago

Can I get help please ​

Can I get help please