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3 years ago

How can i add the fractions using a giant one to create a conmon 1 denominator /4+5/8

1 answer:

8 0

Stack them on top of each other and find the common denominator then multiply to total the denominator. Ex. 1/4 denominator is 8. 4x2 is 8. So 1 times what equals 8. 1! Then you should a new fraction 8/8 which is equivalent to 1.

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PLEASE HELP!!!! TYSM GUYS!!!

ANEK [815]

Answer:

The answer is B: Store Z has the best sale price of $28.

Step-by-step explanation:

Store X: $29.75

Store Y: $30

Store Z: $28

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

7 0

2 years ago

Read 2 more answers

a man casts a 3 feet long shadow. if the suns rays strike the ground 62°, what is the height of the man?

Romashka [77]

Answer:

h = 3*tan(62) where h is the height

Step-by-step explanation:

You basically have a right triangle. the standing man is the vertical line, the shadow is the horizontal line and the 62 degrees is the angle betweenthe horizontal line and the hypotenuse.

So, relative to the angle we have the adjacent angle and opposite. What uses those? Tangent. tan(x) = opp / adj

tan(62) = h/3

h = 3*tan(62) where h is the height

7 0

2 years ago

The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that

Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital 2002 Inpatient Ratio 2002 Outpatient Ratio

1 68 54

2 100 75

3 71 53

4 74 56

5 100 74

6 83 71

Let $\mu_1$ = mean cost-to-charge ratio for outpatient care

$\mu_2$ = mean cost-to-charge ratio for impatient care.

SO, Null Hypothesis, $H_0$ : $\mu_1 \geq \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, $H_A$ : $\mu_1 < \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1_+_n_2_-_2$

where, $\bar X_1$ = sample mean cost-to-charge Outpatient Ratio = $\frac{\sum X_1}{n_1}$ = 63.83

$\bar X_2$ = sample mean cost-to-charge Impatient Ratio = $\frac{\sum X_2}{n_2}$ = 82.67

$s_1$ = sample standard deviation for Outpatient Ratio = $\sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} }$ = 10.53

$s_2$ = sample standard deviation for Impatient Ratio = $\sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} }$ = 14.33

$n_1$ = sample of hospital for outpatient care = 6

$n_2$ = sample of hospital for outpatient care = 6

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2} }{6+6-2} }$ = 12.574

So, the test statistics = $\frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6} } }$ ~ $t_1_0$

= -2.595

The value of t test statistics is -2.595.

Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0

3 years ago

Put the equation y =x^2-8x + 12 into the form y(x-h)^2+k Answer: y =

zlopas [31]

Answer:

y = (x - 4)² - 4

Step-by-step explanation:

y = x² - 8x + 12

y = ( x² - 2(4)x + 4² ) - 4² + 12

y = (x - 4)² - 4

7 0

2 years ago

Sharon mowed eight lawns in four hours at the rate how long would it take her to now ten lawns ?plz help(18points) it has to do

ivanzaharov [21]

(8/4) = (10/x)
8x = 4 x 10
8x= 40
x = 40/8
x=5
It will take 5 hours.

7 0

3 years ago

Read 2 more answers