Answer:
mean of this demand distribution = 100
Step-by-step explanation:
To find the mean of this demand distribution;
Mean = Expected vale = E[x]
for discrete provability function,
we say E[x] = ∑(x.p(x))
x p(x) x.p(x)
10 0.1 1
30 0.4 12
60 0.4 24
90 0.7 63
∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )
∑(x.p(x)) = 100
Answer:
graph B
Step-by-step explanation:
the interval between the two runs is short compare to graph A
