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3 years ago

8

How do I write 11x-8y=-48 in slope intercept form?

1 answer:

klio [65]3 years ago

3 0

The slope-intercept form: y = mx + b

11x - 8y = -48 |subtract 11x from both sides

-8y = -11x - 48 |divide both sides by (-8)

y = 11/8x + 6

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Find the 7th term in the sequence <br> 2,8,32,128

Anuta_ua [19.1K]

Answer:

8192

Step-by-step explanation:

The pattern here is that each term multiplied by 4 is the next number. You can keep multiplying by 4 until you reach the 7th term. So the 5th term will be 128x4 = 512. The 6th term will the 512x4 = 2048. And finally, the 7th term will be 2048x4 = 8192.

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3 years ago

Given: KLMN is a trapezoid, m∠N= m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 root5 Find: KM

Alla [95]

Answer:

The length of KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, $\frac{LM}{KN}=\frac{3}{5}$ , F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since $\frac{LM}{KN}=\frac{3}{5}$ , therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of KM is $\sqrt{109}$ units.

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3 years ago

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BabaBlast [244]

47/12 or 3.9166... or 3 11/12

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likoan [24]

The correct answer, I believe is 13230, hope it helps!!

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The town recreation department ordered 100 balls and bats for the summer baseball camp. Balls cost $4.50 each, and bats cost $20

oksian1 [2.3K]

Answer:

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Step-by-step explanation:

Set up a system of equations where x is the number of balls and y is the number of bats:

x + y = 100

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Solve by elimination by multiplying the top equation by -20, then combine the equations together:

-20x - 20y = -2000

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Then, plug in 76 as x in the first equation to solve for y:

x + y = 100

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So, 76 balls and 24 bats were purchased.

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3 years ago

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