The hl theorem is a special case of the

Mathematics

2 answers:

ratelena [41]3 years ago

6 0

Answer:

The HL theorem is special case of side-side-side postulate.

Step-by-step explanation:

We have been given an incomplete sentence and we are supposed to fill in the missing expression for our given sentence.

Sentence:

The hl theorem is a special case of the_______.

We know that Hypotenuse-Leg theorem of right triangles states that if one leg and hypotenuse of any triangle is equal to one leg and hypotenuse of another triangle, then both triangles are congruent.

By corresponding parts of congruent triangles are congruent the third side of 1st triangle will be congruent to third side of 2nd triangle, so, the both triangles are congruent by S-S-S postulate.

Therefore, the missing expression for our given statement is and side-side-side postulate.

yawa3891 [41]3 years ago

3 0

The HL theorem is a special case of the SSS postulate.

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love history [14]

Answer:

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Step-by-step explanation:

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3 years ago

sarah can complete a project in 90 minutes and her sister betty can complete it in 120 minutes if they both work on the project

alukav5142 [94]

Answer:

It will take them approximately 51.43 minutes to complete the project together

Step-by-step explanation:

This is what is called a "shared job" problem.

The best way to work on them is to start by finding the "portion" of the job done by each of the people in the unit of time.

So, for example, Sarah completes the project in 90 minutes, so in the unit of time (that is 1 minute) she completed 1/90 of the total project

Betty completes the project in 120 minutes, so in the unit of time (1 minute) she completes 1/120 of the total project.

We don't know how long it would take for them to complete the project when working together, so we call that time "x" (our unknown).

Now, when they work together completing the entire job in x minutes, in the unit of time they would have done 1/x of the total project.

In the unite of time, the fraction of the job done together (1/x) should equal the fraction of the job done by Sarah (1/90) plus the fraction of the job done by Betty. This in mathematical form becomes:

$\frac{1}{x} =\frac{1}{90} +\frac{1}{120}\\\frac{1}{x} =\frac{4}{360} +\frac{3}{360}\\\frac{1}{x} =\frac{7}{360} \\x=\frac{360}{7} \\x=51.43\,\,min$