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Nastasia [14]
3 years ago
7

Suppose a triangle has sides a,b, and c, and that a^2+b^2>c^2. Let theta be the measure of the angle opposite the side of len

gth c. Which of the following must be true?
Check all that Apply.

A. theta or delta is an acute angle.
B. The triangle is not a right triangle.
C. cos0>0
D. The triangle is a right triangle.

Mathematics
2 answers:
xenn [34]3 years ago
4 0
B
b 
b 
b i think it will be b
emmasim [6.3K]3 years ago
3 0

Answer with explanation:

It is given that , a triangle having side length , a , b and c follow the Inequality

 →→ a² + b² > c²

→c²-a²-b² <0 or, a²+b²-c²>0 -------(1)

Law of Cosines

c²=a²+b²-2 a b cos C

→ a²+b²-c²= 2 a b cos C

→ 2 a b cos C >0------[Using (1)]

Here, ∠C=theta

So, cos (Theta) > 0

B. The triangle is not a right triangle.

Option B and Option C

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The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
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The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2 units up to form polygon A′B′C′D′. Match each vertex of polygon A′B′C′D′ to its coordinates.Tiles
(2, 1)A′(2, -1)
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8 0
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3 years ago
The perimeter of a triangle is 53 feet. One side of the triangle is 12 feet shorter than the second side. The third side is is 4
grandymaker [24]

Let the shortest side be = a, then side b = 2·a and side c = (b + 24)

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sorry if i am wrong

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3 years ago
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