1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serjik [45]
3 years ago
6

What is product of x/3 and when 6/x y ne0 ?

Mathematics
1 answer:
artcher [175]3 years ago
8 0

Step-by-step explanation:

im not sure... did you figure it out?!?!

You might be interested in
Jeremy lost his dog, and wants to make some signs to put up in the neighborhood. The cost to make 8 paper signs and 2 laminated
Mashcka [7]

Answer:

cost to make paper signs = $1

cost to make laminated signs = $2

Step-by-step explanation:

Let

x = cost to make paper signs

y = cost to make laminated signs

8x + 2y = 12 (1)

10x + 10y = 30 (2)

Multiply (1) by 5

40x + 10y = 60 (3)

10x + 10y = 30 (2)

Subtract (2) from (3) to solve for x

40x - 10x = 60 - 30

30x = 30

x = 30/30

x = $1

Substitute x = 1 into (1)

8x + 2y = 12

8(1) + 2y = 12

8 + 2y = 12

2y = 12 - 8

2y = 4

y = 4/2

y = $2

cost to make paper signs = $1

cost to make laminated signs = $2

5 0
3 years ago
What is the following product?<br> 3V24•3V45 3V69 4(3V6) 6(3V5) 6(3V10)
lora16 [44]

Answer:

option 3

Step-by-step explanation:

6(3√5)

3 0
2 years ago
Solve this equation<br> 0,5 (5-7x)=8-(4x+6)
EleoNora [17]

Answer:

x = 1

Step-by-step explanation:

5-7x = 8-4x-6

5-7x = -4x+2

5 = 3x+2

3 = 3x

x = 1

6 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
2) Find x if IW = x -2 and IU = 2x - 6<br> H<br> U<br> A) 6.6<br> C) 7<br> B) 5<br> D) 4
Mrac [35]

Given:

The figure of a triangle.

IW= x-2

IU=2x-6

To find:

The value of x

Solution:

From the given figure it is clear that VI is a median of the given triangle. It means I divides UW is two equal parts.

IU=IW

2x-6=x-2

2x-x=6-2

[tex]x=4/tex]

The value of x is 4. Therefore, the correct option is D.

5 0
3 years ago
Other questions:
  • Prove the identity <br> 2sin^2x - 1 = sin^2x - cos^2x
    15·2 answers
  • Help me please thank you
    13·1 answer
  • Rewrite the equation below in standard form y=-4x-2
    11·2 answers
  • Calcule senx, sabendo que cosx= -√3/3 e π
    9·1 answer
  • Evaluate the expression for x = 5, y = 3, and z = 14. <br><br> 5x−6y+20z4yz
    11·2 answers
  • Need both boxes filled plz thanks
    5·1 answer
  • Make a line plot for each set of data.
    14·1 answer
  • Solve for x!!!!!!! Plzzzz
    5·2 answers
  • Can I please get help
    6·2 answers
  • How do you learn quantitative variables without getting confused so quick?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!