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3 years ago

I need help but not that much I’m I supposed to find the gCf are the lcm are add subtract multiply are divided

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

3 0

You are not making ANY sense!

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Helppp please!!!!!!!!!!!!!

GrogVix [38]

Answer:

423.9

Step-by-step explanation:

Area 1 = 3.14 (16²) = 803.84

Area 2 = 3.14 (11²) = 379.94

803.84 - 379.94 = 423.9

4 0

3 years ago

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The area of a circle, in terms of

Vedmedyk [2.9K]

Answer:

Radius of a circle= $\sqrt[2]{17} m$

Step-by-step explanation:

As we know, area of a circle=π x $r^{2}$

So give area= 68π $m^{2}$

= 68π=π x $r^{2}$

Simplify ( Cancel the similar signs)

= $r^{2}$ = 68

= r = $\sqrt{68}$ = $\sqrt{4 * 17}$

= r = $\sqrt[2]{17} m$

Hope it helps

Peace

And a brainliest would be really appreciated

3 0

2 years ago

Use the definition of continuity and the properties of limits to show that the function f(x)=x sqrtx/(x-6)^2 is continuous at x

qaws [65]

Answer:

The function is continuous at x = 36

Step-by-step explanation:

From the question we are told that

The function is $f(x) = x * \sqrt{ \frac{x}{ (x-6) ^2 } }$

The point at which continuity is tested is x = 1

Now from the definition of continuity ,

At function is continuous at k if only

$\lim_{x \to k}f(x) = f(k)$

$\lim_{x \to 36}f(x) = \lim_{n \to 36}[x * \sqrt{ \frac{x}{ (x-6) ^2 } }]$

$= 36 * \sqrt{ \frac{36}{ (36-6) ^2 } }$

$= 7.2$

Now

$f(36) = 36 * \sqrt{ \frac{36}{ (36-6) ^2 } }$

$f(36) = 7.2$

So the given function is continuous at x = 36

because

$\lim_{x \to 36}f(x) = f(36)$

7 0

3 years ago

I don't get this how do you do this

aivan3 [116]

Answer:

B. -15

Step-by-step explanation:

7 0

3 years ago

Mrs. Bready has a large bag filled with red and green cards. She tells the class that 15% of the cards are red and 85% are green

Nostrana [21]

Answer:

Let 00-15 = red. Let 16-99 = green.

Step-by-step explanation:

7 0

3 years ago

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