Please help.<br> Is algebra.

adelina 88 [10]

Answer:

. In conclusion, people have to become aware of the dangerous impact fossil fuels have on a long term, and how important it is to shift slowiy to renewable energy resources. However, since the use of renewable energy is a rather new development, it carries the weight of critics and careful long term observation. COuntries have to show commitment to renewable energy and have to evaluate which energy resources are cost-effective and the best with regards to their circumstances The only hindrance of using more renewable energy resources in future could be the finances to install these technologles.

5 0

2 years ago

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Skylar and Rodrigo each recorded how far they traveled while skateboarding. Skylar traveled 65 feet in 5 seconds and Rodrigo tra

Elena-2011 [213]

Skylar went 13ft per second
Rodrigo went 13 1/2 ft per second
So, 1/2 a ft per second

4 0

2 years ago

Number seven on the page

prohojiy [21]

Multiply 9.75 by 1.5 to get 14.63 fluid ounces.

6 0

2 years ago

8.652<br> 10)<br> 1.2<br> Help please

icang [17]

Answer:

1.921

Step-by-step explanation:

7 0

1 year ago

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An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

2 years ago

Please help. Is algebra.