Please help.<br> Is algebra.

Please answer all of these questionS!!! I’m begging you this is urgent

ehidna [41]

Answer:

1. 3x-4.7

2. 4x-11

3. 7x-5

4.4x-10

5. 3x-1

6. 8x-10

Step-by-step explanation:

1. 1x-1.2+2x-3.5

2. 5x-7-x-4

3. 28x+11-21x-16

4. 6x-7-2x-3

5. 5x-2-2x+1

6. 14x+11-6x-21

7 0

3 years ago

The product of a number and negative three is twenty-seven. Which of the following could represent this statement?

alexgriva [62]

Answer:

sorryyyyyuuuuuuuuuuuuuuuuuuu

4 0

3 years ago

Read 2 more answers

Find two positive numbers satisfying the given requirements. The product is 432 and the sum of the first plus three times the se

kogti [31]

Answer:

Step-by-step explanation:

Let the two positive integers be x and y.

If their product is 432, then

xy = 432 ......... 1

Also if the sum of the first plus three times the second is a minimum, then;

p(x) = x + 3y

From 1;

y = 432/x ..... 3

Substitute 3 into 2;

p(x) = x+3y

p(x)= x + 3(432/x)

p(x) = x + 1296/x

Since the expression is at minimum when dp(x)/dx = 0

dp/dx = 1 + (-1296)/x²

dp/dx = 1 -1296/x²

0 = 1 -1296/x²

0 = (x²-1296)/x²

cross multiply

0 = x²-1296

x² = 1296

x = √1296

x = 36

Since xy = 432

36y = 432

y = 432/36

y = 12

Hence the two positive numbers are 36 and 12

4 0

3 years ago

Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries

kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

So

$\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04$

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535
$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465$

64.65% probability of at least one injury commuting to work in the next 20 years

3 0

3 years ago

a vial of medicine contains 60 ounces of medicine. if a dose consists of 3 ounces how many doses does the vial have

Alika [10]

You would do 60/3 and then answer would be 20 doses

6 0

3 years ago

Read 2 more answers

Please help. Is algebra.