Answer:
Q1. y = 5 Q2. (√2 - √3)/2
Step-by-step explanation:
Q1
√12 - √147 + y√3 = 0
Taking -√147 and √12 to the right hand side, we have
y√3 = √147 - √12
y√3 = √(3 × 49) - √(3 × 4)
y√3 = √3 × √49 - √3 × √4
y√3 = √3 × 7 - √3 × 2
y√3 = 7√3 - 2√3
y√3 = 5√3
Dividing both sides by √3, we have
y√3/√3 = 5√3/√3
y = 5
Q2
Sin45° - Cos30°
Since Sin45° = √2/2 and Cos 30° = √3/2
Substituting these values into the equation, we have
Sin45° - Cos30° = √2/2 - √3/2
Taking L.C.M of both factors, we have
Sin45° - Cos30° = (√2 - √3)/2
Answer:
122
Step-by-step explanation:
Plug in 1 for x and 11 for y
1 to the power of any number will always equal 1
I hope this helps!
300 ml ... 200 ml
75 ml ... x = ?
If you would like to know what is the final volume of a gas, you can calculate this using the following steps:
300 * x = 200 * 75 /300
x = 200 * 75 / 300
x = 50.0 ml
The correct result would be A. 50.0 ml.
Answer:
The answer to the question is
1.5 hours that is;
When the distance between them is more then 135 miles is after 1.5 hours and they will lose radio contact at 3:30 p.m.
Step-by-step explanation:
We note that
The speed of the military convoy headed north =50 mph
The speed of the convoy headed south = 40 mph
Let t be the time taken for the two convoys to be 135 miles apart
The time taken for the two convoys to be 135 miles apart is given by
50×t miles+ 40×t miles= 135 miles
That is 90×t miles = 135 miles
t = 135/90 = 1.5 hrs
