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Oksana_A [137]
2 years ago
11

Where do you get the 2/5 and 3/5 from

Mathematics
1 answer:
-Dominant- [34]2 years ago
5 0

Answer:

we can get 3/2 as the answer

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6×2p to the second power when p=5​
geniusboy [140]

Answer:

3600

Step-by-step explanation:

Since the question gives you p, you replace p (which is just a placeholder) with 5.

Your equation should look like this:

(6*2(5))^2 = 3600

6 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
Find the complex zeros of x^3+27. write f in factored form
aliina [53]
x^3+27=0
\\x^3+3^3=0
\\(x+3)(x^2-3x+9)=0
\\x^2-3x+9=0
\\a=1,b=-3,c=9
\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0


4 0
3 years ago
Can you guys please answer this thank you
11111nata11111 [884]

Answer:F B G E A

Step-by-step explanation:

1. F( a rigid transformation only changes the position but the size and angles remain the same)

2. B(The angle of rotation symmetry is the smallest angle the figure can be rotated to coincide with itself.)

3. G(Congruent means that it is the same size and shape)

4. E(Translation moves the whole shape including the points so that the shape and sizes remain the same)

5. A(Though it's position may change, reflective symmetry ensures that no other parts of the shape can change no matter what.)

3 0
2 years ago
Write -2 + 4 + -8 + ...+ 64 +-128 in sigma notation. Then determine the sum.
Grace [21]
It would be -70. Your welcome
4 0
3 years ago
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