Would be the last answer because (n-3)times (n-3) is n^2-6n+9
Answer:
y = 38 + 72t - 16t^2
Step-by-step explanation:
So, solve for t when y=48.
The max height is of course, when t = 64/32 = 2.
Answer:
9x^4-25x^2+16
Step-by-step explanation:
(x^2−1)(3x−4)(3x+4)=(*)
(x^2−1)((3x)^2−4^2) =
(x^2 - 1)(9x^2-16)=
x^2*9x^2 - x^2*16 - 1*9x^2 +16=
9x^4-16x^2-9x^2+16=
9x^4-25x^2+16
(*) (A-B)(A+B) =A^2 - B^2
x=3/2-1/4
8x+2y=12
move the variable to the right side and change the sign.
8x=12-2y
divide both sides of the equation by 8
x=3/2-1/4y
the final solution is
x=3/2-1/4y
Answer:
The projected enrollment is 
Step-by-step explanation:
Consider the provided projected rate.

Integrate the above function.


The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.




Therefore,
Now we need to find 


Hence, the projected enrollment is 