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Vilka [71]
4 years ago
10

Which of the following is the best approximation of the area of a circle whose diameter is 14 feet?

Mathematics
1 answer:
Ray Of Light [21]4 years ago
8 0
Area of a circle is pi x r^2

R = d/2 = 14.2 = 7

Area = 3.14 x 7^2
Area = 3.14 x 49
Area = 153.86 round to 154

Answer is 154 square feet.
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C=100+25h solve for h
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Answer:

h=(c/25)-4

Step-by-step explanation:

c-100 = 25h.   "/25"

(c/25)-4 = h

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3 years ago
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The volume of a cylinder is 12,566.4 cm3. The height of the cylinder is 8 cm.
scoundrel [369]
Using the formulas here: http://www.1728.org/diamform.htm

A)  Volume   =   <span>π <span>• r² • height
radius^2 = Volume / (PI*height)
</span></span><span>radius^2 = 12,566.4 / (PI * 8)
</span>radius^2 =  <span> <span> <span> 500.0011692175 </span> </span> </span>
radius = <span> <span> <span> 22.3607059195 </span> </span> </span>
radius (rounded) = 22.4 cm

B) Area of base = PI * radius^2
Area of base = 3.14159265 * 500
Area of base = <span> <span> <span> 1,570.7963267949 </span>
</span></span><span><span>Area of base (rounded) = </span> 1,570.8 square cm
</span> 
C) <span><span>lateral area = </span>2 • </span><span>π • r • height </span>
<span>lateral area = 2 • </span><span>π • 22.4 * 8
</span>lateral area = <span> <span> <span> 1,125.9468070466 </span> </span> </span>
lateral area = 1,125.9 <span>square cm

D) Total Surface Area = </span><span>(2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
Total Surface Area = <span><span>2 * (top AND bottom area which is the Part B answer times 2) + (the lateral area which is the Part C answer)
</span>
Total Surface Area = </span>( 2 * 1,570.8 ) + (1,125.9)
<span>Total Surface Area = 3,141.6 + 1,125.9
</span><span>Total Surface Area = </span> <span> <span> <span> 4,267.5 </span> </span> </span> square cm





3 0
3 years ago
A circle has diameter 9cm<br> a square has side length 5 cm
Zinaida [17]

Answer:

3

Step-by-step explanation:

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3 years ago
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alisha [4.7K]
Check the picture below.

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does it have an asymptote at 0?  well, surely you can see it right there.

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