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Gennadij [26K]
3 years ago
9

Please help me best answer gets brainliest other answers get five stars and a thanks.

Mathematics
1 answer:
enyata [817]3 years ago
3 0

Dividing by miles per hour is the same as multiplying by hours per mile. You want units of miles and hours to cancel, leaving only units of minutes.

The factor containing minutes must have minutes in the numerator, leaving only the last two selections. The factors containing hours must have hours cancel, leaving only the 3rd selection.

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Rita can make 8 cakes for a bakery each day. So far, she has orders for more than 32 cakes. Right now, Rita needs more than four
Andru [333]

Answer:

x > 4

Step-by-step explanation:

Calling x the number of days Rita needs to bake the total amount of cakes, then inequality is x*8 > 32. Because she has orders for more than 32 cakes and can make 8 cakes per day. Dividing by 8 every side of the inequality gives: x > 4. Graph of the solution is attached (notice that 4 is not included).

5 0
4 years ago
Find the quotient: 3 3/4 ÷ 2
Westkost [7]

Answer:

1\frac{7}{8}

Step-by-step explanation:

4 0
3 years ago
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What is the multiple zero and multiplicity of f(x)=x^3-14x^2+49x
Stella [2.4K]
X^3 - 14x^2 + 49x = 0

Factor an x out:

x(x^2 - 14x + 49) = 0

Find two factors of 49 that add to -14 (-7 and -7). Convert the trinomial to two binomials:

x(x - 7)(x - 7) = 0

The zeros are:

x = 0 and x = 7.

7 occurs as a zero twice and therefore has a multiplicity of 2.

3 0
3 years ago
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Distributive property<br> 7(*+2)+3=73
Elina [12.6K]
X=8 would you like me to explain why?
4 0
3 years ago
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
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