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4 years ago

8(1 + 5x) + 5= 13 + 5x

Mathematics

1 answer:

Rufina [12.5K]4 years ago

7 0

Answer:

0 will be answer as shown in image

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The angle of Oak and Park street is 45 degrees

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Is 3 a factor of 14t-20? Yes No

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What is the equation of a circle with the center of (2,3) and crosses through the point (2,1)

Triss [41]

Answer: (x - 2)² + (y - 3)² = 4

Step-by-step explanation:

The equation of a circle is: (x - h)² + (y - k)² = r² where

(h, k) is the center of the circle
r is the radius of the circle.

Given: (h, k) = (2, 3) and (x, y) = (2, 1)

Input those values to find r²:

(x - h)² + (y - k)² = r²

(2 - 2)² + (1 - 3)² = r²

0 + 4 = r²

4 = r²

Now input (h, k) = (2, 3) and r² = 4 into the equation of a circle:

(x - h)² + (y - k)² = r²

(x - 2)² + (y - 3)² = 4

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3 years ago

6.02 math i need an answer

Katarina [22]

It is A.) or the top left answer.

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3 years ago

The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) =

Cloud [144]

Answer:

$f(x)=3*cosine(x)$

Step-by-step explanation:

We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.

We know that for a sine function $f(x)=sin(x)$ , $f(0)= 0$ ; therefore the function we a looking for cannot be a sine function because it is zero at $x=0$ .

However, the cosine function $f(x)=cos(x)$ gives non-zero value at $x=0:$

$f(0)=cos(0)=1$

therefore, a cosine function can be our function.

Now, cosine function with amplitude $a$ has the form

$f(x)=a*cos(x)$

this is because the cosine function is maximum at $x= 0$ and therefore, has the property that

$f(0)=a*cos(0)= a$

in other words it contains the point $(0, a)$ .

The function we are looking for contains the point $(0, 3)$ ; therefore, its amplitude must be 3, or

$f(x)=3cos(x)$

we see that this function satisfies our conditions: $f(x)$ has amplitude of 3, and it passes through the point (0, 3) because $f(0)=3$

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4 years ago

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