Take 9 time 30 then 9 time 6. Next add them both together.
(9x30)+(9x6)
270+54
324
Answer:
The last choice.
Step-by-step explanation:
![\dfrac{k^2-k-2}{k^2-4k-5}=\dfrac{(k+1)(k-2)}{(k+1)(k-5)}=\dfrac{k-2}{k-5}](https://tex.z-dn.net/?f=%5Cdfrac%7Bk%5E2-k-2%7D%7Bk%5E2-4k-5%7D%3D%5Cdfrac%7B%28k%2B1%29%28k-2%29%7D%7B%28k%2B1%29%28k-5%29%7D%3D%5Cdfrac%7Bk-2%7D%7Bk-5%7D)
The value of k must be restricted from being one that makes the original denominator zero. Hence k ≠ -1 or 5.
Answer: The answer is B
Step-by-step explanation: First, you need to put the twenty over twenty-four for the total amount of shots. Then you simplify the numbers down to five over six.
Answer:
If you mean 10/9 then the answer should be 1.1 repeating itself
Step-by-step explanation:
The answer would be yes because if you take a negative number say, -10 and take it to the power of 3 (cub(e)(ing)) -10^3 you have to take -10* itself 3 times and when you do that the first time that you do that you get this -10*-10=100 but them you still have to times it by -10 one more time because its a cube((-e)ing) meaning 3 so we take it times -10 once more and we get are end answer of 100*-10=-1000.
So to answer your question yes it is possible in a cubing now if this was a squaring then no because a negaive time a negative is always a positive.
Enjoy!=)