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Dmitry_Shevchenko [17]
3 years ago
6

Brandon has 7/1/2gallon of paint. He plans on using 1/1/2 gallon on each room. How many rooms will he be able to paint.

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0
7 because all the room contain 1//2 and Brandon has 7/1/2 i t pretty easy <span />
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BRAINLIEST BRAINLIEST <br> please answer thank you
Anna [14]

Answer:

y + x = 7

Step-by-step explanation:

Standard form should be

y - 9 = -(x+2)

y = -x -2 +9

y + x = 7

6 0
3 years ago
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Find the missing angle..? x=?
Sedaia [141]

Answer:

x = 95°

Step-by-step explanation:

x and 95 are vertical angles and congruent, thus

x = 95°

7 0
3 years ago
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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
4 years ago
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
Kruka [31]

Answer:

Step-by-step explanation:

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of type A paint

x2 = sample mean of type B paint

s1 = sample standard deviation type A paint

s2 = sample standard for type B paint

n1 = number of samples of type A paint

n2 = number of samples of type B paint

From the information given,

x1 = 75.7

s1 = 4.5

n1 = 11

x2 = 64.3

s2 = 5.1

n2 = 9

x1 - x2 = 75.7 - 64.3 = 11.4

√(s1²/n1 + s2²/n2) = √(4.5²/11 + 5.1²/9) = √4.709

Degree of freedom = (n1 - 1) + (n2 - 1)

df = (11 - 1) + (9 - 1) = 18

For the 98% confidence interval, the z score from the t distribution table is 2.552

Margin of error = 2.552√4.709 = 5.55

The upper boundary for the confidence interval is

11.4 + 5.55 = 16.95 hours

The lower boundary for the confidence interval is

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The correct option is

B. 5.85 hrs < μ1 - μ2 < 16.95 hrs

4 0
3 years ago
A set of 5 numbers has a mode of 12 a median of 11 a mean of 10 what could the numbers be?
BabaBlast [244]
The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.

The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}

Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}

Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15

So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number. 

So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
4 0
3 years ago
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