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ddd [48]
3 years ago
10

A store owner had 42 pounds of almonds, 38.5 pounds of walnuts, and 62.5 pounds of peanuts. If the owner splits the peanuts equa

lly into 5 jars, how many pounds of peanuts will each jar contain?
Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Each jar will have 12.5 lbs of peanuts.

Step-by-step explanation:

62.5/5=12.5. The other nuts are irrelevent.

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Which formula shows a joint variation?
djyliett [7]

The answer is the first option: I, II and III.

The explanation is shown below:

1. By definition, there is a joint variation  when a variable depends on two or more different variables. Therefore, you can express it as following:

y=kxz

Where x,y and z are the variables and k is the constant of proportionality.

As you can see, y is directly proportional to x and z.

2. Keeping the information above, you have:

I) V=lwh (V varies jointly with l, w and h.

II) V=\frac{1}{3}r^{2}h\pi (If \frac{\pi}{3} is the constant of proportionality, V varies jointly with r^{2} and h).

III) V=Bh (V varies jointly with B and h.

8 0
3 years ago
Read 2 more answers
How can we write 4y = 5x - 12 in y = mx + b?
Y_Kistochka [10]

Answer:

y=\frac{5}{4}x-3

Step-by-step explanation:

Hope this helps!

=)

4 0
3 years ago
Read 2 more answers
Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
the sum of total amount of money is distributed equally to some girl If there has been five girls less than each of them get Rs.
Arturiano [62]

Step-by-step explanation:

Let the sum of rupee be x

no of boys be y

then each boy get x/y

now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y .........(1)

now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2)

7 0
3 years ago
What's halfway between 3100and4000
Anni [7]
3950 is in between
is the answer
4 0
3 years ago
Read 2 more answers
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