1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ddd [48]
3 years ago
10

A store owner had 42 pounds of almonds, 38.5 pounds of walnuts, and 62.5 pounds of peanuts. If the owner splits the peanuts equa

lly into 5 jars, how many pounds of peanuts will each jar contain?
Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Each jar will have 12.5 lbs of peanuts.

Step-by-step explanation:

62.5/5=12.5. The other nuts are irrelevent.

You might be interested in
Is 1.88 rational or is it irrational
Anna11 [10]

Answer:

1.88 is a irrational number

3 0
3 years ago
6% of x = 1.2; what is x
Ket [755]

Answer:

x =20

Step-by-step explanation:

6% of x = 1.2

Change percent to decimal form

.06x = 1.2

Divide each side by .06

.06x / .06 = 1.2/.06

x =20

4 0
3 years ago
Read 2 more answers
The ratio 36:60 is equivalent to what other ratio
Dmitrij [34]

Answer:

3:5

Step-by-step explanation:

Rewrite this as a fraction to see easier:

\frac{36}{60}

You can divide both numbers by 12, the GCF:

\frac{36}{60}= \frac{3}{5}

Rewrite as a ratio:

3:5

<em>Finito.</em>

<em />

Make 36:60 equivalent to _:50

With the simplified version of 36:60, 3:5, Multiply both sides by ten to get 5 to 50:

3*10:5*10\\30:50

Done.

7 0
3 years ago
Read 2 more answers
have two one-quart jars; the first is filled with water, and the second is empty. I pour half of the water in the first jar into
vfiekz [6]

Answer:

water in quarts is in the first jar after 10th pour = 12/11

Step-by-step explanation:

Let X represent first jar and Y represents second jar.

  • have two one-quart jars; the first is filled with water, and the second is empty

Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.

Lets give the initial value of 0 to the second as it is empty.

So before any pour, the values are:

X: 2

Y: 0

  • pour half of the water in the first jar into the second

After first pour the value of jar X becomes:

Previously it was 2.

Now half of water is taken i.e. half of 2

2 - 1 = 1

So X = 1

The value of jar Y becomes:

The half from jar X is added to second jar Y which was 0:

After first pour the value of jar Y becomes:

0 + 1 = 1

Y = 1

  • a third of the water in the second jar into the first

After second pour the value of jar X becomes:

Previously it was 1.

Now third of the water in second jar Y is added to jar X

1 + 1/3

=  (3 + 1)/3

= 4/3

X = 4/3

After second pour the value of jar Y becomes:

Previously it was 1.

Now third of the water in Y jar is taken and added to jar X so,

1 - 1/3

=  (3 - 1)/3

= 2/3

Y = 2/3

  • a fourth of the water in the first jar into the second

After third pour the value of jar X becomes:

Previously it was 4/3.

Now fourth of the water in the first jar X is taken and is added to jar Y

= 3/4 * (4/3)

= 1

X = 1

After third pour the value of jar Y becomes:

Previously it was 2/3

Now fourth of the water in the second jar X is added to jar Y

= 2/3 + 1/4*(4/3)

= 2/3 + 4/12

= 1

Y = 1

  • a fifth of the water in the second jar into the first

After fourth pour the value of jar X becomes:

Previously it was 1

Now fifth of the water in second jar Y is added to jar X

= 1 + 1/5*(1)

= 1 + 1/5

=  (5+1) / 5

= 6/5

X = 6/5

After fourth pour the value of jar Y becomes:

Previously it was 1.

Now fifth of the water in Y jar is taken and added to jar X so,

= 1 - 1/5

= (5 - 1)  / 5

= 4/5

Y = 4/5

  • a sixth of the water in the first jar into the second

After fifth pour the value of jar X becomes:

Previously it was 6/5

Now sixth of the water in the first jar X is taken and is added to jar Y

5/6 * (6/5)

= 1

X = 1

After fifth pour the value of jar Y becomes:

Previously it was 4/5

Now sixth of the water in the first jar X is taken and is added to jar Y

= 4/5 + 1/6 (6/5)

= 4/5 + 1/5

= (4+1) /5

= 5/5

= 1

Y = 1

  • a seventh of the water in the second jar into the first

After sixth pour the value of jar X becomes:

Previously it was 1

Now seventh of the water in second jar Y is added to jar X

= 1 + 1/7*(1)

= 1 + 1/7

=  (7+1) / 7

= 8/7

X = 8/7

After sixth pour the value of jar Y becomes:

Previously it was 1.

Now seventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/7

=  (7-1) / 7

= 6/7

Y = 6/7

  • a eighth of the water in the first jar into the second

After seventh pour the value of jar X becomes:

Previously it was 8/7

Now eighth of the water in the first jar X is taken and is added to jar Y

7/8* (8/7)

= 1

X = 1

After seventh pour the value of jar Y becomes:

Previously it was 6/7

Now eighth of the water in the first jar X is taken and is added to jar Y

= 6/7 + 1/8 (8/7)

= 6/7 + 1/7

= 7/7

= 1

Y = 1

  • a ninth of the water in the second jar into the first

After eighth pour the value of jar X becomes:

Previously it was 1

Now ninth of the water in second jar Y is added to jar X

= 1 + 1/9*(1)

= 1 + 1/9

=  (9+1) / 9

= 10/9

X = 10/9

After eighth pour the value of jar Y becomes:

Previously it was 1.

Now ninth of the water in Y jar is taken and added to jar X so,

= 1 - 1/9

=  (9-1) / 9

= 8/9

Y = 8/9

  • a tenth of the water in the first jar into the second

After ninth pour the value of jar X becomes:

Previously it was 10/9

Now tenth of the water in the first jar X is taken and is added to jar Y

9/10* (10/9)

= 1

X = 1

After ninth pour the value of jar Y becomes:

Previously it was 8/9

Now tenth of the water in the first jar X is taken and is added to jar Y

= 8/9 + 1/10 (10/9)

= 8/9 + 1/9

= 9/9

= 1

Y = 1

  • a eleventh of the water in the second jar into the first

After tenth pour the value of jar X becomes:

Previously it was 1

Now eleventh of the water in second jar Y is added to jar X

= 1 + 1/11*(1)

= 1 + 1/11

= (11 + 1) / 11

= 12/11

X = 12/11

After tenth pour the value of jar Y becomes:

Previously it was 1.

Now eleventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/11

=  (11-1) / 11

= 10/11

Y = 10/11

3 0
3 years ago
What is the constant term in the expression 24xy -5yz + 82z - 62
Ivanshal [37]

\text{The constant term is the term that doesn't have a variable in it}\\\\\text{As you can see in the expression 24xy -5yz + 82z - 62, the only term}\\\text{that doesn't have a variable is -62}\\\\\text{This means that -62 would be your constant term}\\\\\boxed{\text{Constant term: -62}}

6 0
3 years ago
Other questions:
  • An 8 by 2 arrangement of 16 labels fills one sheet of paper.  How many sheets are needed for 1,488 labels?   A. 744   B. 186   C
    5·1 answer
  • Plss give step by step solutions !!!!!​
    13·1 answer
  • Josh just finished building a dog house.now he wants to put carpet on the floor of the doghouse.josh measured the perimeter of t
    10·1 answer
  • Carla bought quail eggs for 10 cents each. She bought 42 eggs. How much did she pay for
    15·1 answer
  • Mrs. Linda has 17.16 cups of brownie mix. If each
    8·1 answer
  • Convert 3 √5^2 to fraction
    13·1 answer
  • Answer nyo po to...Ang hirap(;-;)....pls. Lang po
    13·1 answer
  • Helpppppppppppppppppppppppppp
    9·1 answer
  • 4 and 1 over 4 divided by 1 and 7 over 8
    8·1 answer
  • The width of a rectangle is 6 less than the length. A second rectangle with perimeter 54, is 3 wider and 2 shorter than the firs
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!