Answer:
Rate of interest r = 2.83 % (Approx.)
Step-by-step explanation:
Given:
Amount invested p = $2,600
Amount get A = $4,300
Number of year n = 18
Find:
Rate of interest r
Computation:
A = p(1+r)ⁿ
4,300 = 2,600(1+r)¹⁸
(1+r)¹⁸ = 1.653846
Rate of interest r = 2.83 % (Approx.)
No.. because you won’t have enough
The total price that Peter paid for the local parcel = $2.07
The rate per ounce at that time was = $0.23/ounce
Total weight of Peter's package = Total price paid by peter/ rate per ounce
Total weight of Peter's package = $2.07/$0.23 per ounce
We now have to divide 2.07/0.23 = 207/23 (Shifting both numerator and denominator by 2 decimal places) = 9
Total weight of Peter's package = 9 ounces
Answer:
Yes, both np and n(1-p) are ≥ 10
Mean = 0.12 ; Standard deviation = 0.02004
Yes. There is a less than 5% chance of this happening by random variation. 0.034839
Step-by-step explanation:
Given that :
p = 12% = 0.12 ;
Sample size, n = 263
np = 263 * 0.12 = 31.56
n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44
According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004
Z = (x - mean) / standard deviation
x = 22 / 263 = 0.08365
Z = (0.08365 - 0.12) / 0.02004
Z = −1.813872
Z = - 1.814
P(Z < −1.814) = 0.034839 (Z probability calculator)
Yes, it is unusual
0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.
