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vfiekz [6]
4 years ago
12

Evaluate a2b2c2 for a = 2, b = 3, and c = 4.

Mathematics
2 answers:
olchik [2.2K]4 years ago
6 0
2(2)2(3)2(4)=192 because you're multiplying everything together in order to find your answer and also because the variables which are the letters represent the numbers that need to be multiplied idk if that made sense but that's the answer lol
Leviafan [203]4 years ago
5 0

Answer:  The required value is 576.

Step-by-step explanation:  We are given to evaluate the following expression for a = 2, b = 3 and c = 4 :

E=a^2b^2c^2.

To do the evaluation, we need to substitute the values of a, b and c in the given expression.

Therefore, the value of the given expression can be calculated as follows :

E\\\\=a^2b^2c^2\\\\=2^2\times 3^2\times4^2\\\\=4\times9\times16\\\\=576.

Thus, the required value is 576.

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Write an equation for the function graphed below. The y intercept is at (0,0.5)
soldier1979 [14.2K]

<em><u>The equation of the graphed function is;</u></em>

f(x) = -3/[(x + 3)(x - 2)]

  • From the given graph, we see that the vertical assymptotes are at x = -3 and x = 2.

This means that at values of x = -3 or x = 2, the denominator becomes zero and the function becomes undefined.

  • This means that, -3 and 2 are roots of the denominator. Thus, the equation of the denominator is;

(x + 3)(x - 2)

  • Now,we see that the y-intercept is (0, 0.5). This means that when x = 0, y = 0.5.

  • Let the numerator of the equation of the function be named a.

Thus, we have;

f(x) = a/((x + 3)(x - 2))

At (0, 0.5), we have;

0.5 = a/((0 + 3)(0 - 2))

0.5 = a/(-6)

Multiply both sides by -6 to get;

-3 = a

  • Thus, the equation of the function is;

f(x) = -3/((x + 3)(x - 2))

Read more at; brainly.com/question/14829729

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