(2,88)
(6,64)
(9,46)
(15,10)
first find y=mx+b
88=-6(2)+b
b=100
y=-6x+100
then plug for y and solve for x or vise versa.
Hopes this loves
Answer:
![\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
Step-by-step explanation:
Rationalize the denominator, then use a common root for the numerator.
![\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\\\\=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\cdot\dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{2^{\frac{1}{4}+\frac{2}{3}}3^{\frac{1}{4}}}{2}\\\\=\dfrac{2^{\frac{11}{12}}3^{\frac{3}{12}}}{2}=\dfrac{\sqrt[12]{2^{11}3^{3}}}{2}\\\\=\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B4%5D%7B6%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5Ccdot%5Cdfrac%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B2%7D%7B3%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D3%5E%7B%5Cfrac%7B3%7D%7B12%7D%7D%7D%7B2%7D%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B2%5E%7B11%7D3%5E%7B3%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
Answer:
Step-by-step explanation :
a) 75
b) 39
C) 182
I'm thinking this is what the problem looks like:

. The first thing to do is to move the

over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this:

. The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.