Answer:
Required number is 4.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of ten times the integer and seven times it’s square is 152.
= > Ten times of a + seven times of it's square = 152
= > 10( a ) + 7( a )^2 = 152
= > 10a + 7a^2 - 152 = 0
= > 7a^2 + 10a - 152 = 0
= > 7a^2 + ( 38 - 28 )a - 152 = 0
= > 7a^2 + 38a - 28a - 152 = 0
= > a( 7a + 38 ) - 4( 7a + 38 ) = 0
= > ( a - 4 )( 7a + 38 ) = 0
= > a = 4 or - 38 / 7
Hence the required number is 4.
The first step to solving this is to multiply both sides of the equation by 3
8 + 10y = 9y - 12
now move the variable to the left side and change its sign
8 + 10y - 9y = -12
move the constant to the right side and change its sign
10y - 9y = -12 - 8
collect the like terms for y
y = -12 - 8 (it equals 1 when you subtract 10 from 9 which is the same is simply saying "y")
calculate the difference on the other side of the equals sign
y = -20
this means that the correct answer to your question is -20.
let me know if you have any further questions
:)
You can use the quadratic formula with it which will be easier
or simple factoring
it will be (5x-11)(7x+4)
Answer:
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Step-by-step explanation:
