Each of the sides of a square $S_1$ with area $16$ is bisected, and a smaller square $S_2$ is constructed using the bisection po ints as vertices. The same process is carried out on S_2 to construct an even smaller square $S_3$. What is the area of $S_3$?
2 answers:
Answer:
4 sq. units
Step-by-step explanation:
Because the vertices of S₂ are the midpoints of S₁, the area of S₂ will be half of that of S₁ which is 16 / 2 = 8. Similarly, because the same process is carried out on S₂ to make S₃, the area of S₃ is 8 / 2 = 4 sq. units.
Answer:
hope this helps friend
Step-by-step explanation:
A = a^2
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